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Anton [14]
2 years ago
13

What additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS? Check all that apply.

Mathematics
2 answers:
12345 [234]2 years ago
5 0

Answer:

choice 1 and choice 5 are the answers

Maksim231197 [3]2 years ago
4 0

Answer: ∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE  are the additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS.

Step-by-step explanation:

Given: ΔXYZ and ΔEFG such that ∠X=∠F

To prove they are congruent by using ASA or AAS conruency criteria

we need only one angle and side.

1. ∠Z ≅ ∠G(angle) and XZ ≅ FG(side)

so we can apply ASA  such that ΔXYZ ≅ ΔFEG.

2. ∠Z ≅ ∠G (angle)and ∠Y ≅ ∠E (angle), we need one side which is not present here.∴we can not apply ASA  such that ΔXYZ ≅ ΔFEG.

3. XZ ≅ FG (side) and ZY ≅ GE (side), we need one angle which is not present here.∴we can not apply ASA  such that ΔXYZ ≅ ΔFEG.

4. XY ≅ EF(side) and ZY ≅ FG(side), not possible.

5. ∠Z ≅ ∠G(angle) and XY ≅ FE(side),so we can apply ASA  such that

ΔXYZ ≅ ΔFEG.

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Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil
kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

A = L^{2}

Donde:

L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

L^{2}< 125\,dados^{2}

Esto nos lleva a decir que:

L < 11.180\,dados

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

n = (11\,dados)^{2}

n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

4 0
2 years ago
A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random
Harlamova29_29 [7]

Answer with explanation:

Given : Sample mean =\overline{x}=\text{48.47 pounds}

Standard deviation : \sigma=\text{ 3.1 pounds.}

Sample size : n = 36

Claim : \mu\neq50

∴ H_0:\mu=50

H_1:\mu\neq50

Since the alternative hypothesis is two tail , then the test is two tail test.

By using a z statistic and a 0.05 level of significance. Reject  H_0 if z < -1.960 or is z> 1.960.

Then , the test static for population mean is given by :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

z=\dfrac{48.47-50}{\dfrac{3.1}{\sqrt{36}}}\approx-2.96

We reject H_0 since -2.96\leq -1.96. We have statistically significant evidence at \alpha=0.05 to show that the mean amount of garbage per bin is not different from 50.  

5 0
2 years ago
For the month of June, Mae Green budgeted the following amounts: $180 for food, $475 for rent, $15 for transportation, $50 for i
ycow [4]
Question 1

Total budget = 180 + 475 + 15 + 50 + 65 + 25 + 150 + 30 = $990
Real spending = 182 + 475 + 12 + 65 + 68 + 12.50 + 150 + 36  = $1000.5

Mae Green didn't stay within the allocated budget

---------------------------------------------------------------------------------------------------------

Question 2

Eleanor:
Income = 380.48
Spending = 16.50

Peter:
Income = 120 + 13.65 + 100 = 233.65

Total income = 233.65 + 380.48 - 16.50 = 597.63

-------------------------------------------------------------------------------------------------------------

Question 3

Total spent = 540 + 48.55 + 34.15 + 12.80 + 18.95 + 38.60 + 2 + 6.50 = 701.55

-------------------------------------------------------------------------------------------------------------

Question 4 

Marie's new balance = 250.65 - [21.95+48.50+75.60] + 55 = $159.50

------------------------------------------------------------------------------------------------------------

Question 5

[235/825] × 100 = 28.48%
4 1
2 years ago
Read 2 more answers
Which answer choice contains all the factors of 10
RSB [31]
Factors of 10 are : 1,2,5,10
7 0
2 years ago
Sharon is decreasing the size of a diagram of a leaf that is 30 centimeters long by 10 centimeters wide if the reduced diagram i
Lyrx [107]
Do it in ratio form, 30/10=x/4, 30*4=120/10=12. it will be 12 centimeters long

4 0
2 years ago
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