Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer:
Train b is moving faster than a by 45 units an hour
Step-by-step explanation:
8 = 4N - 2.8
Add 2.8
10.8 = 4N
Divide 4
2.7 million is the population in Nevada
The
<u>correct diagram</u> is attached.
Explanation:
Using technology (such as Geogebra), first construct a line segment. Name the endpoints C and D.
Construct the perpendicular bisector of this segment. Label the intersection point with CD as B, and create another point A above it.
Measure the distance from C to B and from B to D. They will be the same.
Measure the distance from A to B. If it is not the same as that from C to B, slide A along line AB until the distance is the same.
Using a compass and straightedge:
First construct segment CD, being sure to label the endpoints.
Set your compass a little more than halfway from C to D. With your compass set on C, draw an arc above segment CD.
With your compass set on D (the same distance as before) draw an arc above segment CD to intersect your first arc. Mark this intersection point as E.
Connect E to CD using a straightedge; mark the intersection point as B.
Set your compass the distance from C to B. With your compass on B, mark an arc on EB. Mark this intersection point as A.
AB will be the same distance as CB and BD.
2t + w = 10
4t + 2w = -20
4t + 2w = 20
4t + 2w = -20
There is no solution to this system of equations.