The answer:
<span>the upper and lower control limits (uclim and lclim) for mean formula is
for the mean chart
uclim= x+A2xR
where x = sum(of the value) / number of each value
and for
lclim=</span>x+A2xR
<span>
R is the range such that R= Xmax - Xmin
in the case of the sample 1: S1
the data are:
79.2 78.8 80.0 78.4 81.0
the mean is x1 = (</span>79.2 + 78.8 + 80.0 + 78.4 + 81.0) / 5= 79.48
<span>its range is R 1= 81.0 -78.4 = 2.6
we can do the same method for finding the mean chart and range for all samples
</span>S2: x2=<span> 80.14 , R2=2.3
</span>S3: x3= 80.14 , R3=1.2
S4: x4= 79.60 , R4=1.7
S5: x5= 80.02 , R5=2.0
S6: x6=80.38 , R6=1.4
<span>
therefore the average value is X= sum( x1+x2+...+x6) / 6 = 79.96
and R=sum(R1+R2+...+R6)/6=1.87
finally
range chart uclim =D4xR=3.95 and lclim is always equal to 0, because D3=0
we can say that the process is not in control.
</span>
Answer:
(36 - 10) (divide sign) 6
Step-by-step explanation:
Walk through the problem:
"subtract 10 from 36." = "take ten away from 36." = "36 - 10."
"then divide by 6." = "Divide 36 - 10 by 6." = "(36 - 10) divided by 6."
This is the answer:
(3m^-2 n)^-3 / 6mn^-2
1st step: distribution of power3^-3 m^-2*-3 n^-3 / 6mn^-2
2nd step: use product and quotient rulem^6 n^2/ 3^3 *6*m*n^3
3rd and last step: simply expressionm^5/162n
The answer is m^5/162n
Hope this helps. :)
There is a 1/3 chance or 33% chance that the other ball is also red.
We first calculate the average of the ten data points. 9 + 7 + 6.5 + 7.5 + 7 + 8 + 5 + 6 + 7.5 + 8 = 71.5, and 71.5 / 10 = 7.15.
Then we find the sum of squares of deviations from the mean:
(9 - 7.15)^2 + (7 - 7.15)^2 + (6.5 - 7.15)^2 + (7.5 - 7.15)^2 + (7 - 7.15)^2 + (8 - 7.15)^2 + (5 - 7.15)^2 + (6 - 7.15)^2 + (7.5 - 7.15)^2 + (8 - 7.15)^2 = 11.525
Then we divide by the number of terms = 10, so the variance of the sample will be 11.525 / 10 = 1.15.
