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Alchen [17]
1 year ago
15

Which expression is equivalent to (3m^-2n)^-3/6mn^-2? Assume m=0, n=0.

Mathematics
2 answers:
goldenfox [79]1 year ago
8 0
This is the answer:

(3m^-2 n)^-3 / 6mn^-2
1st step: distribution of power3^-3 m^-2*-3 n^-3 / 6mn^-2
2nd step: use product and quotient rulem^6 n^2/ 3^3 *6*m*n^3
3rd and last step: simply expressionm^5/162n
The answer is m^5/162n

Hope this helps. :)
pentagon [3]1 year ago
8 0
The answer is m^5/162n
Solution:
(3m^-2 n)^-3 / 6mn^-2
So you must distribute the power3^-3 m^-2*-3 n^-3 / 6mn^-2
And use product and quotient rulem^6 n^2/ 3^3 *6*m*n^3
Lastly, simply expression
m^5/162n

This will give you the answer of
m^5/162n
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