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Paha777 [63]
2 years ago
9

The student senate at a local university is about to hold elections. A representative from the women’s sports program and a repr

esentative from the men’s sports program must both be elected. Two candidates, an incumbent and a challenger, are vying for each position and early polling results are presented next. A hypothesis test must be performed to determine whether the percentages of supporting votes are different between the two incumbent candidates. In a sample of 100 voters, 67 said that they would vote for the women’s incumbent candidate. In a separate sample of 100 voters, 55 said they would vote for the men’s incumbent candidate. Let p1 and p2 be the proportions of supporting votes for the incumbent candidates representing women’s and men’s sports programs, respectively. Which of the following are the competing hypotheses to determine whether the percentages of supporting votes are different between the two incumbent candidates?a. H0: p1 ≤ p2, Ha: p1 > p2.b. H0: p1 ≥ p2, Ha: p1 < p2.c. H0: p1 = p2, Ha: p1 ≠ p2.d. H0: p = p0, Ha: p ≠ p0.
Mathematics
1 answer:
Amanda [17]2 years ago
6 0

Answer: H0: p1 ≤ p2, Ha: p1 > p2

Step-by-step explanation:

According to the information obtained, we can say that the hypothesis that determines that the percentages of support votes are different between the two incumbent candidates is as follows

H0: p1 ≤ p2, Ha: p1> p2

where the null hypothesis represents the difference between proportions

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Let us say that:

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P = payment or amount that she receives every week

 

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The amount that she receives for A must be greater than she receives for choice B, so:

110 x > 150 + 85 x                       (inequality equation)

 

Calculate for x:

110 x – 85 x > 150

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x > 6

 

Therefore Nadia must sell more than 6 ads every week so that Choice A would be the better choice.

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Mary throws a plastic disc to her friend. Her friend catches the disc six seconds after Mary throws it. The table shows the heig
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Answer:

A=4 B=3

Step-by-step explanation:

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2 years ago
Which statement correctly names the congruent triangles and justifies the reason for congruence? ΔABC ≅ ΔFDE by HL ΔABC ≅ ΔFED b
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Looking at the given diagram,

Side AC = Side DF = 3.2

Side AB = Side FE = 4 units

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Since two sides and one angle are equal, then triangle FED = triangle ABC by SAS(side angle side)

This makes the ratios possible

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One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples
JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

X₁: score of a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± t_{n_1+n_2-2;1-\alpha /2} * Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11

t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708

[(82.3-81.2) ± 1.708* (6.11*\sqrt{\frac{1}{15}+\frac{1}{12}  }]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

3 0
2 years ago
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