Let us say that:
x = is the number of ads that Nadia sold every week
P = payment or amount that she receives every week
So the equations we can formulate for choice A and B are:
choice A: P = 110 x
choice B: P = 150 + 85 x
The amount that she receives for A must be greater than
she receives for choice B, so:
110 x > 150 + 85 x (inequality equation)
Calculate for x:
110 x – 85 x > 150
25 x > 150
x > 6
Therefore Nadia must sell more than 6 ads every week so
that Choice A would be the better choice.
The answer to the question is 300 square feet
Answer: The correct option is ΔABC ≅ ΔFED by SAS
Step-by-step explanation:
Looking at the given diagram,
Side AC = Side DF = 3.2
Side AB = Side FE = 4 units
Angle A = angle F = 72 degrees
Since two sides and one angle are equal, then triangle FED = triangle ABC by SAS(side angle side)
This makes the ratios possible
AB/FE = AC/DF
The HL given means hypotenuse leg. It will not hold because the triangles are not right angle triangles.
Answer:
Step-by-step explanation:
Hello!
To test if boys are better in math classes than girls two random samples were taken:
Sample 1
X₁: score of a boy in calculus
n₁= 15
X[bar]₁= 82.3%
S₁= 5.6%
Sample 2
X₂: Score in the calculus of a girl
n₂= 12
X[bar]₂= 81.2%
S₂= 6.7%
To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.
To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.
Then you can calculate the interval as:
[(X[bar]_1-X[bar_2) ±
*
]


[(82.3-81.2) ± 1.708* (6.11*
]
[-2.94; 5.14]
Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.
I hope this helps!