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OLga [1]
2 years ago
6

Which statement correctly names the congruent triangles and justifies the reason for congruence? ΔABC ≅ ΔFDE by HL ΔABC ≅ ΔFED b

y SAS ΔABC ≅ ΔDEF by HL ΔABC ≅ ΔDEF by SAS Thank you!

Mathematics
1 answer:
pishuonlain [190]2 years ago
3 0

Answer: The correct option is ΔABC ≅ ΔFED by SAS

Step-by-step explanation:

Looking at the given diagram,

Side AC = Side DF = 3.2

Side AB = Side FE = 4 units

Angle A = angle F = 72 degrees

Since two sides and one angle are equal, then triangle FED = triangle ABC by SAS(side angle side)

This makes the ratios possible

AB/FE = AC/DF

The HL given means hypotenuse leg. It will not hold because the triangles are not right angle triangles.

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For a certain type of copper wire, it is knownthat, on the average, 1.5 flaws occur per millimeter.Assuming that the number of f
mario62 [17]

Answer:

The probability that no flaws occur in a certain portion of wire of length 5 millimeters =  1.1156 occur / millimeters

Step-by-step explanation:

<u>Step 1</u>:-

Given data A copper wire, it is known that, on the average, 1.5 flaws occur per millimeter.

by  Poisson random variable given that λ = 1.5 flaws/millimeter

Poisson distribution P(X= r) = \frac{e^{-\alpha } \alpha ^{r} }{r!}

<u>Step 2:</u>-

The probability that no flaws occur in a certain portion of wire

P(X= 0) = \frac{e^{-1.5 } \(1.5) ^{0} }{0!}

On simplification we get

P(x=0) = 0.223 flaws occur / millimeters

<u>Conclusion</u>:-

The probability that no flaws occur in a certain portion of wire of length 5 millimeters = 5 X P(X=0) = 5X 0.223 = 1.1156 occur / millimeters

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