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Alecsey [184]
2 years ago
12

nadia was offered a job for selling ads cor a magazine. She must agree to one of the following paymen options. CHOICE A:$110 for

each ad she sells. CHOICE B:a weekly salary of $150,plis $85 for each ad she sells .Wriye and solve an inequality to determine the number of adds nadia would need to sell per week in order for Choice A to be a better choice
Mathematics
1 answer:
Fittoniya [83]2 years ago
6 0

Let us say that:

x = is the number of ads that Nadia sold every week

P = payment or amount that she receives every week

 

So the equations we can formulate for choice A and B are:

choice A: P = 110 x

choice B: P = 150 + 85 x

 

The amount that she receives for A must be greater than she receives for choice B, so:

110 x > 150 + 85 x                       (inequality equation)

 

Calculate for x:

110 x – 85 x > 150

25 x > 150

x > 6

 

Therefore Nadia must sell more than 6 ads every week so that Choice A would be the better choice.

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The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
2 years ago
Which percentage of weight was lost if a patient weighed 102 kg and is currently 96 kg?
galina1969 [7]

Answer:

Step-by-step explanation:

you have to make a box like this:

║ ---------- ║------------ ║     label one side percent and the other amount

║   x%     ║    96 kg  ║

║ _    _   _║_____ _║   Now if the patient originally weighed 102 kg which

║100%    ║    120 kg ║    is 100% place the numbers in the bottom box.

║ _  _  _  ║ _   _   _ ║     and if the patient currently weighs 96 kg then let

 Percent     Amount       percentage of the weight lost be x. Now cross multiply.  You should get 100*96=120*x. Simplify that to get 9600=120x, now divide by 120 on both sides and you get 80 so x= 80. But the problem isn't done yet. Now you have to subtract 80% from 100% to find the weight lost, because 80% is the percentage of the current weight. after you have subtracted you get 20

20% of the original weight was lost.

4 0
2 years ago
The batting Wang Xiu Ying uses to fill quilts has a thermal conductivity rate of 0.030.030, point, 03 watts (\text{W})(W)left pa
Semenov [28]

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

the batting wang xiu ying uses to fill quilts has a thermal conductivity rate of 0.03 watts (W) per meter(m) per degree celsius. what is the batting thermal conductivity when w/cm•c

Given

K = 0.03W/m°C

Required

Convert K to W/cm°C

Since 1m = 100cm,

K = 0.03w/1×100cm°C

K = 3×10^-2w/10² cm°C

K = 3 × 10^-2w/10² cm°C

K = 3w× 10^{-2-2}cm°C

K = 3w×10^-4cm°C

K = 0.0003w/cm°C

8 0
2 years ago
A catering company prepared and served 300 meals at an anniversary celebration last week using eight workers. The week before, s
swat32

Answer:

II case.

Step-by-step explanation:

Given that a catering company prepared and served 300 meals at an anniversary celebration last week using eight workers.

The week before, six workers prepared and served 240 meals at a wedding reception.

Productivity is normally measured by number of outputs/number of inputs

Here we can measure productivity as

no of meals served/no of workers

In the I case productivity =\frac{300}{8} \\=37.5

In the II case productivity = \frac{240}{6} \\=40

Obviously II case productivity is more as per worker 40 meals were served which is more than 37.5 meals per worker in the I case.

3 0
2 years ago
Consider all seven-digit numbers that can be created from the digits 0-9 where the first and last digits must be odd and no digi
Natali [406]

Answer:

Considering all seven-digit numbers that can be created from the digits 0-9 I could deduce that you can make 100 , 700, 800 even infinite numbers

6 0
2 years ago
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