1)
.
2)
.
3) The particle is moving right when the velocity function is positive:
or
.
4) When
the particle is slowing down because the acceleration is close to zero
the particle is speeding up when acceleration is increasing away from zero:
.
5)
.
Answer:
For First Solution: 
is the solution of equation y''-y=0.
For 2nd Solution:
is the solution of equation y''-y=0.
Step-by-step explanation:
For First Solution:
In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.
First order derivative:
2nd order Derivative:
Put Them in equation y''-y=0
e^t-e^t=0
0=0
Hence is the solution of equation y''-y=0.
For 2nd Solution:
In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.
First order derivative:
2nd order Derivative:
Put Them in equation y''-y=0
cosht-cosht=0
0=0
Hence is the solution of equation y''-y=0.
Answer:
3/10+4/10=7/10
Step-by-step explanation:
For this question you would have to expand the numbers to the thounsandths
so it can be 9.181, 9.182, 9.183 and so on
The hypotenuse of the way that they have taken is equal to 2 miles. Jogging this distance with a rate of 5 miles per hour will take Jesse 0.4 hours. Further, for Mark to be back to the starting point, the total distance covered is 2.75. Dividing the distance by 12 miles per hour, it will take Mark only 0.23 hours. Thus, Mark will reach the initial point first.
