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1 year ago

6

A twizzler factory makes regular 8in, king size 10in, extra long 16in, and snack size 3in twizzlers. Before packaging the candy,

the size is checked and any pieces that have a percent error of 1.5% or more are rejected. Would every size of twizzler be rejected for being 0.14in too short? Why or why not?

1 answer:

serious [3.7K]1 year ago

8 0

Answer:

Step-by-step explanation:

fdsdfghjhgv njhgfghj nbhgvfgbh nhgvfbhg huygvbh huyvg hbv

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The area of the rectangle is 64.8 square centimeters. What is the perimeter of the rectangle? One group of ten tenths and one gr

9966 [12]

Answer:

(a) $Perimeter = 32.2\ cm$

(b) 100

Step-by-step explanation:

Solving (a):

Given

Shape: Rectangle

$Area = 64.8$

Required

Calculate the perimeter.

Area is calculated as:

$Area = L * W$

Where

$L = Length$ and $W = Width$

Substitute 64.8 for Area

$64.8 = L * W$

Make L the subject:

$L = \frac{64.8}{W}$

Perimeter is calculated as:

$P = 2 * (L + W)$

Substitute 64.8/W for L

$P = 2 * (\frac{64.8}{W} + W)$

$P = \frac{129.6}{W} + 2W$

To solve further, we take the derivative of P and set it to 0, afterwards.

$dP = -\frac{129.6}{W^2} + 2$

Set to 0

$0 = -\frac{129.6}{W^2} + 2$

Collect Like Terms

$\frac{129.6}{W^2} = 2$

Cross Multiply:

$2W^2= 129.6$

Divide through by 2

$W^2 = 64.8$

Take square roots

$W = \sqrt{64.8$

$W = 8.05$

Recall that:

$L = \frac{64.8}{W}$

So:

$L= \frac{64.8}{8.05}\\$

$L= 8.05$

The perimeter is:

$Perimeter = 2 * (8.05 + 8.05)$

$Perimeter = 2 * (16.10)$

$Perimeter = 32.2\ cm$

Solving (b):

Given

((1 Group of 10 tenths) and (1 group of 8 tenths))/(6 groups of 3 tenths)

Required

Solve

$Tenths = \frac{1}{10}$

So, the expression becomes:

((1 Group of $10 * \frac{1}{10}$ ) and (1 group of $8 * \frac{1}{10}$ ))/(6 groups of $3 * \frac{1}{10}$ )

This gives:

((1 Group of $\frac{10}{10}$ ) and (1 group of $\frac{8}{10}$ ))/(6 groups of $\frac{3}{10}$ )

Group means product, so the expression becomes:

$\frac{(1 * \frac{10}{10} \ and\ 1 * \frac{8}{10})}{6 * \frac{3}{10}}$

And, as used here means addition

$\frac{(1 * \frac{10}{10} + 1 * \frac{8}{10})}{6 * \frac{3}{10}}$

Simplify:

$\frac{(1 * 1 + 1 * 0.80)}{6 *0.30}$

$\frac{(1 + 0.80)}{1.80}$

$\frac{1.80}{1.80}$

$= 1.00$

7 0

1 year ago

24. ABCDE and PQRST are regular pentagons.

SIZIF [17.4K]

Answer:

126°

Step-by-step explanation:

In quadrilateral DSRC, SR || DC (given)

AP = BQ = CR = DS = ET (given)

$\therefore$ CR bisects $\angle DCB$

$\therefore m\angle DCR=\frac{108\degree}{2}$

( $108\degree$ is the measure of an angle of pentagon)

$\therefore m\angle DCR=54\degree$

$\because m\angle DCR + m\angle SRC=180\degree$

(Measure of interior angles on the same side of transversal)

$\therefore 54\degree + m\angle SRC=180\degree$

$\therefore m\angle SRC=180\degree- 54\degree$

$\therefore m\angle SRC=126\degree$

3 0

2 years ago

9. Karl is putting a frame around a rectangular photograph. The photograph is

iren [92.7K]

Answer:

120in.

Step-by-step explanation:

The pic attached

4 0

1 year ago

The function y=7500(1.08)t represents the value y of an investment after t years. What is the value of the investment after 6 ye

boyakko [2]

Answer:

The answer is 48600, but I'm not entirely sure if it correct.

From what I know, if I were to see ¨y=7500(1.08)t¨, we could have to substitute the t with the number of years. Looking like this, ¨y=7500(1.08) x 6¨.

The reason I don know if my answer is correct or not since I don know if you have the t next to 1.08 to represent that or to simply multiply the property of it with 6 (the number of years).

So I tried...

Step-by-step explanation:

4 0

1 year ago

A boat on the ocean is 2 mi from the nearest point on a straight? shoreline; that point is 15 mi from a restaurant on the shore.

Sladkaya [172]

Answer:

a) x = 0,70 miles

T = 1/2* (√4 + x²) +( 15 - x )/3 Objective Function to minimize

b) V(min) = 2.59 m/hr

Step-by-step explanation:

Let assume the boat is in Point A, she lands in point B, and R is the restaurant

Let call x distance between the point O in which perpendicular line from the boat get to shoreline, and the point were she land.

We know distance is

d = v*t ⇒ t = d/v

She rows at 2 miles/hr and walk at 3 miles /hr

According to that she takes

c (hypotenuse) of right triangle AOB/ 2 rowing

and 15 - x /3 walking

Total time is:

T = c/2 + ( 15-x )/3 c =√(2)² + x² ⇒ T = [√(2)² + x² ] /2 + ( 15-x )/3

T = 1/2* (√4 + x²) +( 15 - x )/3 (1)

And that is the Objective function to minimize

a) Taking derivatives on both sides of the equation we get

T´(t) = x /( √4 + x²) - 1/3 ⇒ T´(t) = 0 x /( √4 + x²) - 1/3 = 0

3*x - √( √4 + x²) = 0 ⇒ 3*x = √( √4 + x²)

Squaring both sides

9x² = 4 + x² ⇒ 8x² = 4 x² = 1/2 x = 0,70 miles

If we plug this value in the Objective function we will get the minimum time

1/2* (√4 + x²) +( 15 - x )/3 ⇒ [√ 4 + 0,5] /2 + 14,3/3 = T (min)

T(min) = 1.06 + 4.77 = 5.83 hr

Distance L (hypotenuse of right triangle AOR)

L = √(2)² + (15)² L = 15,13 miles

And that distance have to be traveled at least in 5.83 hr rowing

Then as v = d/t V(min) = 15.13/ 5.83 ⇒ V(min) = 2.59 m/hr

6 0

2 years ago