We need to assign a value for x to check the possible values of y.
1st inequality: y < -0.75x
X = - 1 ; y < -0.75(-1) ; y < 0.75 possible coordinate (-1,0.75) LOCATED AT THE 2ND QUADRANT
X = 0 ; y < -0.75(0) ; y < 0 possible coordinate (0,0) ORIGIN
X = 1 ; y < -0.75(1) ; y < -0.75 possible coordinate (1,-0.75) LOCATED AT THE 4TH QUADRANT
2nd inequality: y < 3x -2
X = -1 ; y < 3(-1) – 2 ; y < -5 possible coordinate (-1,-5) LOCATED AT THE 4TH QUADRANT
X = 0 ; y < 3(0) – 2 ; y < -2 possible coordinate (0,-2) LOCATED AT THE 4TH QUADRANT
X = 1 ; y < 3(1) – 2 ; y <<span> 1 possible coordinate (1,1) LOCATED AT THE 1ST QUADRANT
The actual solution to the system lies on the 4TH QUADRANT.
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A sideways opening parabola is in the form

, so we know from the process of elimination that it will either be b or c. Next we have to realize that if the parabola opens to the left it is a negative parabola, just like if a parabola opens upside down it is a negative parabola. So the one that has the negative out front is b.
Answer:

Step-by-step explanation:
The scale factor described denotes a reduction operation. The missing dimension is given by simple rule of three:


Answer: <em>
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Step-by-step explanation:
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The complete exercise is:"A gardener has 27 tulip bulbs, 45 tomato plants, 108 rose bushes, and 126 herb seedlings to plant in the city garden. He wants each row of the garden to have the same number of each kind of plant. What is the greatest number of rows that the gardener can make if he uses all the plants?"</em></h3><h3 />
The first step to solve the exercise is to find the Greatest Common Factor (GCF) between 27, 45, 108 and 126.
You can follow these steps in order to find the GCF:
1. You must decompose 27, 45, 108 and 126into their prime factors:

2. You must multiply the commons with the lowest exponents. Then:
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Therefore, the greatest number of rows that the gardener can make if he uses all the plants is:

Equation:
a = 5120
r = 1 + .2 = 1 . 2
f (n ) = 5120 * 1 . 2^n - 1
N = 4 years
f ( 4 ) 5120 * 1 . 2^4 - 1
5120 * 1 . 2^3
We want to know, The number of Highway Accidents in Four Years.
Answer: 8,847 Highway Accidents total:
Hope that helps!!!!!!!!!!! : )