Answer:
Option d. PQ = YZ
Step-by-step explanation:
<u><em>The question in English is</em></u>
Choose the most appropriate answer. The PQR triangle and the XYZ triangle are two congruent triangles. The angle P = the angle Y and PR = YX. Side pairs of the same length are ... a. PQ = XZ b. QR = YZ c. QR = XY d. PQ = YZ
we know that
If two triangles are congruent, then its corresponding sides and its corresponding angles are congruent
Corresponding sides are named using pairs of letters in the same position on either side of the congruence statement
so
we have that
so
Triangle PQR is congruent with Triangle YZX
That means
<em><u>Corresponding angles</u></em>
<u><em>Corresponding sides</em></u>
Answer:
Step-by-step explanation:
Since we are not told what to find, we can as well find the time taken by the rocket to reach its maximum height as shown
The rocket reaches its maximum height when the velocity is zero
v = dh/dt
v = -32t+64
Since v = 0 at maximum height
0 = -32t+64
32t = 64
t = 64/32
t = 2secs
Hence the rocket reaches the maximum height after 2secs
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
In 1 min it receives 3815/35=109 so in 1 hour it receives 109x60=6540 calls
