The question is incorrect.
The correct question is:
Three TAs are grading a final exam.
There are a total of 60 exams to grade.
(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?
Answer: 60!/(25!20!15!)
Step-by-step explanation:
The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’
n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1
The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:
n!/p! q! r!
Therefore,
The answer is 60!/25!20!15!
Answer:
Not necessarily, because this wasn't an experiment.
Step-by-step explanation:
Answer:
140 is the answer for y2 because x1 is 80 more than x2 so you would subtract y2 by 80
Answer:
$29619.13
Step-by-step explanation:
a. Tara has $14375 in credit card debt and the interest rate is 5.3%.
Now, if f(t) represent the amount of money Tara have in credit card debt, where t is the number of years after after interest begins to accrue, then
......... (1)
Again Tara borrows $570 each month for rent from her parents without any interest.
If g(x) represent the amount of money Tara owes to her parents, where t represents the number of years passed,then we can write
g(t) = 570 × 12t = 6840t ........ (2)
Therefore,
b. So, for t = 2 years,
= $29619.13
So, Tara has to repay $29619.13 if she continues this way without any repayment for 2 years. (Answer)
