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vlada-n [284]
1 year ago
14

A large city in the ancient world was square-shaped. measured in miles, its area numerically exceeded its perimeter by about 132

. find its dimensions. (round to the nearest tenth.
Mathematics
1 answer:
melisa1 [442]1 year ago
7 0
Area = perimeter + 132.  

Let  each side of the city be x miles long, then:-

x^2 = 4x  + 132
x^2 - 4x - 132 = 0

x  =  [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2

x = 13.66, -9.66   We ignore the negative

So the city  has dimension of 13.66 * 13.66

13.7 * 13.7   to nearest 10th
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Leonard used 2/7 of his paycheck to pay his cell phone bill. How much was Leonard's cell phone bill?
FrozenT [24]
The awnser is 6 dollars 

8 0
2 years ago
A student dropped a textbook from the top floor of his dorm and it fell according to the formula s(t) = −16t 2 + 8√t , where t i
Sidana [21]

Answer:

<h2>-29.61m/s</h2>

Step-by-step explanation:

Given the distance of fall of the student in term of the time t expressed by the equation s(t) = −16t² + 8√t, to get the average speed of fall of the pencil after 2.8 secs, we will need to differentiate the given function first since Velocity is the change in distance of a body with respect to time i.e

V = d(s(t))/dt

s(t) = −16t² + 8t^1/2

V = -32t+1/2(8)t^(1/2 - 1)

V = -32t+4t^-1/2

The average speed of the fall Using the fact that the pencil hit the ground in exactly 2.8 seconds, will be gotten by substituting t = 2.8 into the resulting equation.

V = -32t+4(2.8)^-1/2

V = -32t+4/√2.8

V = -32+4/1.6733

V = -32+2.391

v = -29.61m/s

<em>Hence the average speed of the fall is -29.61m/s</em>

3 0
2 years ago
On a baseball field, the pitcher’s mound is 60.5 feet from home plate. During practice, a batter hits a ball 195 feet at an angl
worty [1.4K]

In this problem, we can imagine that all the points connect to form a triangle. The three point or vertices are located on the pitcher mount, the home plate and where the outfielder catches the ball. So in this case we are given two sides of the triangle and the angle in between the two sides.

<span>With the following conditions, we can use the cosine law to solve for the unknown 3rd side. The formula is:</span>

c^2 = a^2 + b^2 – 2 a b cos θ

Where,

a = 60.5 ft

b = 195 ft

θ = 32°

Substituting the given values:

c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32

c^2 = 3660.25 + 38025 – 20009.7

c^2 = 21,675.56

c = 147.23 ft

<span>Therefore the outfielder throws the ball at a distance of 147.23 ft towards the home plate.</span>

8 0
1 year ago
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u
Naddika [18.5K]

Answer with Step-by-step explanation:

We are given that Laplace's equation

u_{xx}+u_{yy}=0

We have to determine given function is  solution of given laplace's equation.

If a  function is solution of given Laplace's  equation then  it satisfy the solution.

1.u=e^{-x}cosy-e^{-y}cosx

Differentiate w.r.t x

Then, we get

u_x=-e^{-x}cosy+e^{-y}sinx

Again differentiate w.r.t x

u_{xx}=e^{-x}cosy+e^{-y}cosx

Now differentiate u w.r.t y

u_y=-e^{-x}siny+e^{-y}cosx

Again differentiate w.r.t y

u_{yy}=-e^{-x}cosy-e^{-y}cosx

Substitute the values in given Laplace's equation

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Hence, given function is a solution of given Laplace's equation.

2.u=sinx coshy+cosx sinhy

Differentiate w.r.t x

u_x=cosx coshy-sinx sinhy

Again differentiate w.r.t x

u_{xx}=-sin x coshy-cosxsinhy

Now, differentiate u w.r.t y

u_y=sinx sinhy+cosx coshy

Again differentiate w.r.t y

u_{yy}=sinx coshy+cosx sinhy

Substitute the values then we get

-sinx coshy-cosxsinhy+sinxcoshy+cosx sinhy=0

Hence, given function is a solution of given Laplace's equation.

4 0
1 year ago
After being dropped from a platform, a ball bounces several times. The graph shows the height of the ball after each bounce.
Paul [167]

<u>Answer-</u>

<em>End behavior for increasing x represents that </em><em>the height of each bounce will approach 0.</em>

<u>Solution-</u>

From the graph the exponential equation is,

y=100e^{(-0.35x)}

From the properties of negative exponential function properties, as x increases, the value of y decreases.

So, in this case, as x or number of bounce increases, y or the height of bounce decreases. And eventually the value becomes zero.

Therefore, end behavior for increasing x represents that the height of each bounce will approach 0.

5 0
2 years ago
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