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barxatty [35]
2 years ago
9

Which congruence theorems can be used to prove ΔEFG ≅ ΔJHG? Select two options.

Mathematics
2 answers:
mezya [45]2 years ago
5 0
<h2><u><em>Answer: </em></u></h2><h2><u><em> </em></u></h2>

ASA  and AAS

<h2><u><em>Step-by-step explanation: </em></u></h2>

We do not know if these are right triangles; therefore we cannot use HL to prove congruence.

We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.

We are given that EF is parallel to HJ.  This makes EJ a transversal.  This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent.  We also know that ∠EGF and ∠HGJ are vertical angles and are congruent.  This gives us two angles and a non-included side, which is the AAS congruence theorem.

Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent.  Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.

choli [55]2 years ago
4 0

Answer:

ASA

Step-by-step explanation:

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The winner of a weight-lifting competition bench-pressed 400 pounds. All other competitors bench-pressed at least 23 pounds less
ch4aika [34]

Answer:

x\le 400-23\\ \\x\le 377\ pounds

Step-by-step explanation:

The winner of a weight-lifting competition bench-pressed weight 400 pounds.

All other competitors bench-pressed at least 23 pounds less. So, the maximum weight that all other competitors bench-pressed is

400-23=977\ pounds

If x pounds is the weight that the other competitors bench-pressed, then

x\le 400-23\\ \\x\le 377\ pounds

that sounds as the other competitors bench-pressed at most 377 pounds weight.

6 0
2 years ago
Can you find the value of x?​
Taya2010 [7]

Answer: 5

Step-by-step explanation: We can use the Pythagorean Theorum here.

4^2 + x^2 = 7^2

16+ x^2 = 49

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x = 5

3 0
1 year ago
Findtheequationoftheaxisofsymmetryfortheparabolay = x2 + 4. Simplify any numbers and write them as proper fractions, improper fr
Misha Larkins [42]
Us 2(x+2)


Factor out from the expression
4 0
1 year ago
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Samara is adjusting a satellite because she finds it is not focusing the incoming radio waves perfectly. The shape of her satell
kozerog [31]

Answer:

(-5.5,0)

Step-by-step explanation:

The question is on finding the focus point of a parabola

Given y²= 2(x+6).....................................(a)

Compare equation (a) with the standard equation  (y-b)²= 2p(x-a)

y²= 2(x+6)------can be written as (y-0)²=2(x+6)

(y-0)²=2(x+6)

(y-b)²= 2p(x-a)

2p=2-----------------divide both sides by 2 to get p

p=2/2=1

For  the vertex (a,b)⇒(-6,0)

For  the focus point ( a+p/2, b)........................................(b)

Substitute values i equation (b) above

(-6+1/2 ,0) =(-5.5, 0)

3 0
2 years ago
Find the exact value for cos π 12 applying sum and difference formulas involving π 3 and π 4 .
nadya68 [22]

First, split the angle into two angles where the values of the six trigonometric functions are known. In this case, π/12 can be split into π/3−π/4.

cos(π/3−π/4)

Use the difference formula for cosine to simplify the expression. The formula states that cos(A−B)=cos(A)cos(B)+sin(A)sin(B)

cos(π/3)⋅cos(π/4)+sin(π/3)⋅sin(π/4)

The exact value of cos(π/3) is 12, so:

(12)⋅cos(π/4)+sin(π/3)⋅sin(π/4)

The exact value of cos(π/4) is √22.

(12)⋅(√22)+sin(π/3)⋅sin(π/4)

The exact value of sin(π/3) is √32.

(12)⋅(√22)+(√32)⋅sin(π/4)

The exact value of sin(π/4) is √22.

(12)⋅(√22)+(√32)⋅(√22)

Simplify each term:

√24+√64

Combine the numerators over the common denominator.

<span>(√2+√6) / 4</span>

8 0
2 years ago
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