Part A the coefficient is 20c and 35w, the variable is c and w representing cost and week. and the constant is 23.50.
Part B He would have 503.50 because <span><span>35</span><span>(12)</span></span>+60<span>=<span><span>420x</span>+<span>60+23.50 which would be 503.50
Part C The coefficient of the cost would change because you would be adding a 5 dollar increase!!!!!! done</span></span></span>
Hello!
We have the following data:
Paula weight (before training) = 65.5 kg
Weight lost by Paula (in training) = 3500 grams = 3.5 kg
Paula's weight (after training) =?
65.5 kg - 3.5 kg = 62 kg (Current weight)
First let's write out the inequality before choosing a graph.
x apples each weighing 1/3 of a pound: 1/3x
y pounds of grapes: y
So...
1/3x + y < 5
The maximum weight is 4 pounds since the total weight of both the grapes and apples are less than 5.
In the y-axis, the first, third, and fourth graphs already exceed the capacity of 5 pounds.
So, by process of elimination, the correct graph for this problem is the second one.
12s, you don’t have a value for s, so the problem can’t be fully solved but if you did you would multiply 12 by her speed
Hope this helps
