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1 year ago

Which of these groups of relative frequencies would be best represented by a pie chart?

Mathematics

1 answer:

SVETLANKA909090 [29]1 year ago

7 0

All of these would be perfectly fine represented by a pie chart except A, which doesn't add to 100%.

The question seems to be getting at the idea that a pie chart might be better when the slices are all visually different sizes. I don't really think that's right; a pie chart for D say, where the two slices are about the same, gives the correct impression of the relative frequencies, which are about the same.

Answer they're looking for: C

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Dying for help please failing mathh

JulsSmile [24]

You might want to stick to at most five questions at once, makes it easier for the rest of us. :)

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Need clarification on anything?

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2 years ago

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g A sailing ship stopped at several islands, releasing one mating pair of goats onto each one. On the large island, the goats' g

PSYCHO15rus [73]

Answer:

The goat population reaches 1000 in 12.4 years

Step-by-step explanation:

After t years, the number of goats is given by

$N = N_0e^{bt}$

where $N_0$ is the initial number of goats and b is the per capita growth rate.

From the question,

$N_0 = 2$
b = 0.5
N = 1000

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1 year ago

Read 2 more answers

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T

Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. In this problem, $\sigma = 0.25$

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.1}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}$

$n = 24.01$

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

$n = 66.7$

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}$

$n = 96.04$

Rounding up, 97

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1 year ago

A city determines that a planned community must have at least 4 acres of developed and open space, and the difference

FinnZ [79.3K]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x -----> the number of open acres

y ----> the number of developed acres

we know that

$x+y \geq 4$ -----> inequality A

$x\leq 1$ ----> inequality B

Remember that

if the number of open acres, x, can be no more than 1. then the number of open acres, x must be less than or equal to 1

Solve the system of equations by graphing

The solution is the shaded area (Note The number of acres cannot be a negative number)

The graph in the attached figure

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1 year ago

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laiz [17]

7x-6y=14
6x-y=-17
x = -4 y = -7 (SOLUTION) ; in ordered pair form (x,y) = (-4,-7)

3x+8y=16
-9x-24y=-48
INFINITE SOLUTIONS: general form = (x,y) = ( x, -(3x/8)+2 )

Edited later:
7x-6y=14
6x-y=-17
From second equation 6x - y = -17, we have y = 6x +17. Substitute this in the first equation to get
7x-6y=14
>> 7x-6(6x+17)=14
>> 7x-36x-102=14
>> 7x-36x=102+14
>> -29x=116
>> x=116/(-29)
>> x=-4

Now plug this value in y = 6x +17, to get
y = 6(-4) + 17 = -24 +17 = -7

So x = -4, y = -7 is the solution.

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1 year ago