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2 years ago

Which of these groups of relative frequencies would be best represented by a pie chart?

Mathematics

1 answer:

SVETLANKA909090 [29]2 years ago

7 0

All of these would be perfectly fine represented by a pie chart except A, which doesn't add to 100%.

The question seems to be getting at the idea that a pie chart might be better when the slices are all visually different sizes. I don't really think that's right; a pie chart for D say, where the two slices are about the same, gives the correct impression of the relative frequencies, which are about the same.

Answer they're looking for: C

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Rachel measured the lengths of a random sample of 100 screws. The mean length was 2.9 inches, and the population standard deviat

MaRussiya [10]

Answer:

z = 10

Step-by-step explanation:

The value of the z-statistic is given by:

$z = \frac{X - \mu}{s}$

In which:

X is the measured value.

$\mu$ is the expected value.

$s = \frac{\sigma}{\sqrt{n}}$ is the standard deviation of the sample. $\sigma$ is the standard deviation of the population.

In this question:

The mean length was 2.9 inches, and the population standard deviation is 0.1 inch.

This means that $\mu = 2.9, \sigma = 0.1$

Random sample of 100 screws.

This means that n = 100.

To see if the batch of screws has a significantly different mean length from 3 inches, what would the value of the z-test statistic be?

3 inches, so $X = 3$

$s = \frac{0.1}{\sqrt{100}} = 0.01$

$z = \frac{X - \mu}{s}$

$z = \frac{3 - 2.9}{0.01}$

$z = 10$

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1 year ago

Steven and Julio each have 13 marbles. Megan has twice the number of marbles as Steven and Julio combined. Steven thinks that me

kodGreya [7K]

Answer:

Step-by-step explanation:

Steven = 13 marbles

Julio = 13 marbles

Megan has twice the number of marbles as Steven and Julio combined

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Among the options (26, 13, 50, 169, 338), the only reasonable estimate is 50

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2 years ago

Using V = lwh, what is an expression for the volume of the following prism? The dimensions of a prism are shown. The height is S

Lubov Fominskaja [6]

<h2>Explanation:</h2><h2></h2>

We know that the volume of a prism is defined by:

$V=lwh \\ \\ \\ Where: \\ \\ l:length \\ \\ w:width \\ \\ h:height \\ \\ \\ l=\frac{d-2}{3d-9} \\ \\ w=\frac{4}{d-4} \\ \\ h=\frac{2d-6}{2d-4}$

Substituting values:

$V=\left(\frac{d-2}{3d-9}\right)\left(\frac{4}{d-4}\right)\left(\frac{2d-6}{2d-4}\right) \\ \\ \\ Simplifying: \\ \\ V=\frac{d-2}{3d-9}\cdot \frac{4}{d-4}\cdot \frac{d-3}{d-2} \\ \\ V=\frac{\left(d-2\right)\cdot \:4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)\left(d-2\right)} \\ \\ V=\frac{4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)} \\ \\ V=\frac{4\left(d-3\right)}{3\left(d-3\right)\left(d-4\right)}$