9×2=18. add the tow zeros like this 9×2=18+00=1,800
The sum of the 18 numbers is 22.5 x 18 = 405.
Let the numbers be x, x + 1, x + 2, . . ., x + 17
Sum of n term of an arithmetic sequence = n/2(a + l)
18/2(x + x + 17) = 405
9(2x + 17) = 405
2x + 17 = 405/9 = 45
2x = 45 - 17 = 28
x = 28/2 = 14
Therefore, the smallest integer is 14.
You want to round 905,154 to the nearest ten-thousands place. The ten-thousands place in your number is shown by the bold underlined digit here:
9<em><u>0</u></em>5,154
To round 905,154 to the nearest ten-thousands place...
The digit in the ten-thousands place in your number is the 0. To begin the rounding, look at the digit one place to the right of the 0, or the 5, which is in the thousands place.
Since the 5 is greater than or equal to 5, we'll round our number up by
Adding 1 to the 0 in the ten-thousands place, making it a 1.
and by changing all digits to the right of this new 1 into zeros.
The result is: 910,000.
So, 905,154 rounded to the ten-thousands place is 910,000.
Answer:
<h3>
If you mean: AC=CE, the answer is: AB = 24</h3>
Step-by-step explanation:
D is the midpoint of CE, then
CD = DE = 0.5CE = 0.5(10x+18) = 5x + 9
So: 5x + 9 = 7x - 1
-9 -9
5x = 7x - 8
-7x -7x
-2x = -8
÷(-2) ÷(-2)
x = 4
AC = CE = 10x + 18 = 40 + 18 = 58
BC = 9x - 2 = 36 - 2= 34
AB = AC - BC = 58 - 34 = 24
Answer:
W=0.8333*t
2.917 ft³
Step-by-step explanation:
At time t=3, there is 2.5 ft³ of water in the tub
Finding the relation will be;
3=2.5
1=?
Rate=0.8333 ft³/min
W=0.8333 ft³ / min
W=0.8333*t
At t=3.5 will be;
1 min = 0.8333
3.5 min =?
Apply cross-production
3.5*0.8333 =2.917 ft³