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2 years ago

Can anyone help me with this?

Mathematics

1 answer:

Maurinko [17]2 years ago

5 0

Answer:

D. -6m²n² + 10m²n + 8mn² - 10mn

Step-by-step explanation:

(-7mn + 8mn² - 8m²n²) + (10m²n + 2m²n² - 3mn)

Apply the distributive property to remove the parentheses

-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn

Combine like terms together and arrange in standard form

-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn

-8m²n² + 2m²n² + 10m²n + 8mn² - 7mn - 3mn

-6m²n² + 10m²n + 8mn² - 10mn

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The mean of a list of 80 numbers is 230. If four numbers 145,156,210, and 255 are added, what is the mean of the list of numbers

anygoal [31]

Add 145, 156, 210. and 255 then divide by 4. The mean equals 184.

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2 years ago

Read 2 more answers

In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

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2 years ago

A customer at Logan’s Plants pays $20.00 for a bush and $11.50 per pack of flowers. The table shows the total cost to purchase o

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Answer:

<h2>brainiest me</h2>

Step-by-step explanation:

how many expensive packs of flower is 3,150$

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2 years ago

What type of triangle has side lengths 12, 13, and 2√3?

Travka [436]

Answer:

The triangle is an obtuse scalene triangle

Step-by-step explanation:

we know that

if $c^{2}=a^{2}+b^{2}$ --------> is a right triangle

if $c^{2}>a^{2}+b^{2}$ --------> is an obtuse triangle

if $c^{2}$ --------> is an acute triangle

where

c is the greater side

we have

$c=13\ units$

$a=12\ units$

$b=2\sqrt{3}\ units$

$c^{2}=13^{2}=169$

$a^{2}+b^{2}=12^{2}+(2\sqrt{3})^{2}=156$

$c^{2}>a^{2}+b^{2}$ -------> is an obtuse triangle

Remember that

The given triangle has three different length side

Is a scalene triangle

therefore

The triangle is an obtuse scalene triangle

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2 years ago

Let a and b be real numbers where a=/b=/c=/0 which of the following functions could represent the graph below?

Tresset [83]

Answer: The second option; y = (x - a)^2*(x-b)^4

Step-by-step explanation:

Ok, we have that a and b are real numbers different than zero.

In the graph, we can see that the line touches the x-axis in two values. Now, if we would have an equation like:

y = x*(x - a)^3*(x - b)^3

then when x = 0 we would have:

y = 0*(0-a)^3*(0-b)^3 = 0

But in the graph, we can see that when x = 0, the value of y is different than zero, so we can discard options 1 and 3.

So the remaining options are:

y = (x - a)^2*(x-b)^4

y = (x - a)^5*(x - b)

Now, another thing you can see in the graph is that it is always positive.

Particularly the second option allows negative values for y because it has odd powers, then we can also discard this option.

(For example, if x > a and x < b we would have a negative value for y)

Then the only remaining option is y = (x - a)^2*(x-b)^4

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2 years ago