Billy's mother had five children. The first was named Lala, the second was named Lele, the third was named Lili, the fourth was
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Answer:
The width of lot B is 11 feet, so option A is correct.
Step-by-step explanation:
Given:
- Two rectangular properties share a common side.
- Lot A is 33 feet wide and 42 feet long.
- The combined area of the lots = 1,848 square feet.
To find:
How many feet wide is Lot B?
Solution:
we know that, area of a rectangle is length x breadth
Then area of lot A = 33 x 42 = 1386 square feet.
And area of lot B = width x 42
Now, we are given that, total area = 1848
area of lot A + area of lot B = 1848
1386 + width x 42 = 1848
width x 42 = 1848 – 1386
width x 42 = 462
width = 11
Hence, the width of lot B is 11 feet, so option A is correct.
Answer:
The area of new pumpkin patch is = 15 x² + 380 x + 2400
Step-by-step explanation:
Given as :
The length of rectangular patch = L = 40 meters
The width of rectangular patch = W = 60 meters
So, The area of rectangular patch = Length × Width
Or, = L × W
So , = 40 meters × 60 meters
Or, = 2400 meters²
Again The Width of new Patch = ( 40 + 3 x ) meter
And The Length of new Patch = ( 60 + 5 x ) meter
Or, = L × W
So , = ( 40 + 3 x ) meters × ( 60 + 5 x ) meters
Or, = 2400 + 200 x + 180 x + 15 x²
Or, = 15 x² + 380 x + 2400
Hence The area of new pumpkin patch is = 15 x² + 380 x + 2400 Answer