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faltersainse [42]
2 years ago
10

What is the product? (-2x-9y^2)(-4x-3)

Mathematics
2 answers:
telo118 [61]2 years ago
6 0

Answer:-8x^2-6x+36xy^2+27y^2

Step-by-step explanation:

using the FOIL method

amid [387]2 years ago
5 0

The product of (-2x-9y^2 )(-4x-3) is 8x^2+27y^2+6x+36xy^2

Explanation:

Given:

(-2x-9y^2 )(-4x-3)

Let the above equation is equal to k

k= (-2x-9y^2 )(-4x-3)

Now, we will solve the right hand side of the above equation  

k=8x^2+6x+36xy^2+27y^2

So, the above equation would become  

k=8x^2+27y^2+6x+36xy^2

So, the final answer of the above product is  

8x^2+27y^2+6x+36xy^2

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Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how
Igoryamba

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune  from the sun

= 4.503  ×  10 ⁹  k m .

and Mercury  =  5.791  ×  10 ⁷ k m .

Hence neptune is (  4.503  ×  10 ⁹) ÷ (5.791 × 10 ⁷  ) times farther from the sun than mercury

i.e.(  \frac{4.503}{5.791} )  × 10⁹⁻⁷ times

=   0.7776  ×  10 ² times

=   77.76  times.

4 0
2 years ago
Alberto is making a budget. He owes a cell phone bill of $60 per month for 23 more months, plus the fees for any extra usage suc
netineya [11]
I'm not sure what your book is saying about the matter but a cell phone is not usually an essential expense. If it is saying it is though, it would be an essential flexible expense. 
3 0
1 year ago
Read 2 more answers
A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th
QveST [7]

we know that

the volume of a cone is equal to

V= \frac{1}{3} \pi r^{2}h

in this problem

the radius is equal to

r= \frac{112}{2}= 56ft

1) <u>Find the height of the cone before the storm</u>

Applying the Pythagorean Theorem find the height

h^{2} = l^{2}-r^{2}

l=65 ft

h^{2} = 65^{2}-56^{2}

h^{2} = 1,089

h=33 ft

2) <u>Find the volume before the storm</u>

V= \frac{1}{3}*\pi* 56^{2}*33

V=34,496\pi\ ft^{3}

3) <u>Find the volume after the storm</u>

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

so

r=(56/3) ft

h=(33/3)=11 ft

V= \frac{1}{3}*\pi* (56/3)^{2}*11

V= 1,277.63\pi\ ft^{3}

<u>4) Find how this change affect the volume of the pile</u>

Divide the volume after the storm by the volume before the storm

\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}

therefore

<u>the answer part a) is</u>

The volume of the pile after the storm is \frac{1}{27} times the original volume

<u>Part b)</u>  Estimate the number of lane miles that were covered with salt

5) <u>Find the amount of salt that was used during the storm</u>

=34,496 \pi - 1,277.63 \pi \\= 33.218.37 \pi \\= 104,358.59\ ft^{3}

6) <u>Find the pounds of road salt used</u>

104,358.59*80=8,348,687.2\ pounds    

7) <u>Find the number of lane miles that were covered with salt</u>

8,348,687.2/350=23,853.39 \ lane\ miles  

therefore

<u>the answer part b) is</u>

the number of lane miles that were covered with salt is 23,853.39 \ lane\ miles

<u>Part c) </u>How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

the remaining salt is equal to 1,277.63\pi\ ft^{3}

1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}

8) <u>Find the pounds of road salt </u>

4,013.79*80=321,103.20\ pounds

9) <u>Find the number of lane miles </u>

321,103.20/350=917.44 \ lane\ miles

therefore

<u>the answer part c) is</u>

the number of lane miles is 917 \ lane\ miles

7 0
2 years ago
Find three different surfaces that contain the curve r(t) = t^2 i + lnt j + (1/t)k
Viefleur [7K]

solution:

Consider the curve: r(t) = t²i +(int)j + 1/t k

X= t² , y = int ,z = 1/t

Using, x = t², z = 1/t

                    X = (1/z)²

Xz²= 1

Using y = int, z= 1/t

Y = in│1/z│

Using x = t², y = int

Y = int

= in(√x)

Hence , the required surface are,

Xz² = 1

Y = in│1/z│

Y= in(√x)


7 0
2 years ago
The epicenter of an earthquake is the point on Earth’s surface directly above the earthquake’s origin. A seismograph can be used
DaniilM [7]

Answer:

I used desmos and plotted all three circles. The point that hey all intersected was (-1, 3).

Step-by-step explanation:

5 0
2 years ago
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