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Aneli [31]
2 years ago
7

The quotient property of radicals requires the indices of the radicals to be the same. Does this mean that it is not possible to

write es002-1.jpg as a single radical? Explain.
Mathematics
2 answers:
Troyanec [42]2 years ago
6 0

The radicands are powers of the same base, so they can be written using rational exponents.

Simplify the quotient of the exponential expressions by getting a common denominator and subtracting exponents.

The simplified expression is the 4th root of y

GaryK [48]2 years ago
4 0
Although the expression is not included, it is possible to assure that the answer is negative.

It is negative because you can express a quotient of radicals as a single radical using the least common index fo the radicals.

Look. This is the quotient property of radicals:
<span>
\frac{ \sqrt[n]{x} }{ \sqrt[n]{y} } = \sqrt[n]{ \frac{x}{y} }

Now, if you have the quotient of two radicals with different indices you drive the radicals to one common index, i.e.  least common index, as per this:

\frac{ \sqrt[n]{x} }{ \sqrt[m]{x} } =  \frac{ \sqrt[m.n]{x.x^m} }{ \sqrt[m.n]{y.y^n} } = \sqrt[m.n]{ \frac{x^{m+1}}{y^{n+1}} }

As, you see it is proved that two any quotient of radicals can be rewriten using the quotient property.
</span>
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Here are Barry Bonds's home-run totals, mostly for the San Francisco Giants, during the years 1991 - 2005:25, 34, 46, 37, 33, 42
elixir [45]

Answer:

Refer the attached figure.

Step-by-step explanation:

Given : Here are Barry Bonds's home-run totals, mostly for the San Francisco Giants, during the years 1991 - 2005

The data A={25, 34, 46, 37, 33, 42, 40, 37, 34, 49, 73, 46, 45, 45}  

To find : Modified box plot for this distribution?

Solution :

Arranging the data from lowest to highest,

{25,33,34,34,37,37,40,42,45,45,46,46,49,73}  

Find the median of the data  

As the data is even numbers so the median is

M=\frac{40+42}{2}=\frac{82}{2}=41

Median = 41

For Box plot Graph,

q_1=Q(A,0)

q_1=25

q_2=Q(A,0.25)

q_2=34.75

q_3=Q(A,0.5)

q_3=41

q_4=Q(A,0.75)

q_4=45.75

q_5=Q(A,1)

q_5=73

Plotting the Box plot of the data.

Refer the attached figure below.

8 0
2 years ago
Read 2 more answers
Choose the product. -7p 3(4p 2 + 3p - 1)
DIA [1.3K]

Answer:

14p -3

Step-by-step explanation:

-7p 3(4p 2+3p - 1)

3x4= 12p

3x3=9p

12+9= 21

21-7=14p

3x2=6

3x-3=-9

-9 +6= -3

= 14p -3

hope this helps :)

7 0
1 year ago
An equation is written to represent the relationship between the temperature in Alaska during a snow storm, y, as it relates to
Serhud [2]

Answer:

either of ...

• quadrant 1 only

• quadrant 1 and 4 only

Step-by-step explanation:

Time since the storm started is always positive. The values of x are positive in quadrants 1 and 4.

Temperatures in a blizzard are not always terribly cold. Some of the coldest snowstorms on record have temperatures in the range of +5 °F to +18 °F. These values are negative temperatures on the Celsius scale, so the quadrant used for plotting them will depend on the temperature scale you choose.

While temperatures in Alaska can be well below zero (on either the F or C temperature scales), the air usually has to warm up to the range indicated above before it can snow. US temperatures are generally reported using the Fahrenheit scale, but weather records are often kept using the Celsius scale.

I would be inclined to choose "Quadrant 1 and 4 only", but arguments can be made for "1 only" and "4 only" as suggested above.

8 0
2 years ago
It is common in many industrial areas to use a filling machine to fill boxes full of product. This occurs in the food industry a
Sphinxa [80]

Answer:

(a) P(B) = 0.008, (b) P(A∩B) = 0, (c) Yes, A and B are mutually exclusive events, (d) P(A∪B)=0.948, (e) 0.948, (f) 0.06

Step-by-step explanation:

We have three different posibilities

A: fill to specification

B: underfill

C: overfill

in probability the sum of the different events which are mutually exclusive should sum to 1, so, we should have

(a) P(B) = 1 - P(A)-P(C) = 1-0.940-0.052=0.008

(b) P(A∩B)=probability that the machine fill to specification and underfill = 0 because a machine can't fill to specification and underfill at the same time

(c) Yes, A and B are mutually exclusive events, because a machine can't fill to specification and underfill at the same time

(d) Because A and B are mutually exclusive events we should have that

P(A∪B)=P(A)+P(B)=0.940+0.008=0.948

(e) The probability that the machine does not overfill is the same that the probability that the machine fill to specification plus the probability that the machine underfill, i.e, the probability that the machine does not overfill is P(A)+P(B)=0.948, because does not overfill is equivalent either to fill to specification or to underfill.

(f) The probability that the machine either overfill or underfills is

P(C∪B)=P(C)+P(B)=0.052+0.008=0.06 because C and B are mutually exclusive events.

5 0
2 years ago
A chef bought some green and red peppers. She bought 18 green peppers, which was 3/4 the total number.
Nezavi [6.7K]
A: Their would be 24 red peppers because I did 18 divided by 3/4 and got 24 and 24 times 3/4 is 18
B:She bought 42 peppers all together because 18 plus 24 is 42
4 0
2 years ago
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