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inna [77]
2 years ago
15

Using V = lwh, what is an expression for the volume of the following prism? The dimensions of a prism are shown. The height is S

tartFraction 2 d minus 6 Over 2 d minus 4 EndFraction. The width is StartFraction 4 Over d minus 4 EndFraction. The length is StartFraction d minus 2 Over 3 d minus 9 EndFraction.
Mathematics
3 answers:
eduard2 years ago
7 0

Answer:

its c on E2020

Step-by-step explanation:

Lubov Fominskaja [6]2 years ago
4 0
<h2>Explanation:</h2><h2></h2>

We know that the volume of a prism is defined by:

V=lwh \\ \\ \\ Where: \\ \\ l:length \\ \\ w:width \\ \\ h:height \\ \\ \\ l=\frac{d-2}{3d-9} \\ \\ w=\frac{4}{d-4} \\ \\ h=\frac{2d-6}{2d-4}

Substituting values:

V=\left(\frac{d-2}{3d-9}\right)\left(\frac{4}{d-4}\right)\left(\frac{2d-6}{2d-4}\right) \\ \\ \\ Simplifying: \\ \\ V=\frac{d-2}{3d-9}\cdot \frac{4}{d-4}\cdot \frac{d-3}{d-2} \\ \\ V=\frac{\left(d-2\right)\cdot \:4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)\left(d-2\right)} \\ \\ V=\frac{4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)} \\ \\ V=\frac{4\left(d-3\right)}{3\left(d-3\right)\left(d-4\right)}

Finally: \\ \\  \boxed{V=\frac{4}{3\left(d-4\right)}}

Guest1 year ago
0 0

Using V = lwh, what is an expression for the volume of the following prism?

The dimensions of a prism are shown. The height is StartFraction 2 d minus 6 Over 2 d minus 4 EndFraction. The width is StartFraction 4 Over d minus 4 EndFraction. The length is StartFraction d minus 2 Over 3 d minus 9 EndFraction.
StartFraction 4 (d minus 2) Over 3 (d minus 3)(d minus 4) EndFraction
StartFraction 4 d minus 8 Over 3 (d minus 4) squared EndFraction
StartFraction 4 Over 3 d minus 12 EndFraction
StartFraction 1 Over 3 d minus 3 EndFraction

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Let A be the event 'the first inhabitant speaks the truth' and B the event the person you asked speaks the truth'

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Therefore, in this problem, we want to know P(A ∩ B | (A∩ B) ∪ (A^c ∩ B^c) )

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P(A ∩B | (A∩ B) ∪ (A^c ∩ B^c) )  = P(A∩ B)/P((A∩ B) ∪ (A^c ∩ B^c))  = (1/9) / (4/9) = 1/4.

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\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

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