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lana [24]
2 years ago
15

the area of a Blackboard is 1 1/3 square yards posters area is 8/9 square yards find the unit rate and explain in words with uni

t rate means in the context of this problem is in more than one unit that can be calculated how do you know
Mathematics
2 answers:
ehidna [41]2 years ago
8 0

Answer:

Unit rate of area of blackboard to area of poster = \frac{8}{33}

Unit rate of area of Poster to area of blackboard = = \frac{33}{8}              

Step-by-step explanation:

Rates help us to evaluate or compare two different quantities.

Unit rate help us to compare or know that how the  units of the quantity 1 is related to units of quantity 2.

We are given that:

Area of Blackboard = \frac{11}{3}

Area of Poster = \frac{8}{9}

Unit rate of area of blackboard to area of poster: It mean that how does unit area of blackboard is related to or corresponds to area of poster

= \frac{\text{Area of Poster}}{\text{Area of Blackboard}} = \frac{\frac{8}{9} }{\frac{11}{3} }

= \frac{8}{33}

Thus, 1 unit area of blackboard corresponds to \frac{8}{33}\text{ area of poster}

Unit rate of area of Poster to area of blackboard: It mean that how does unit area of poster is related to or corresponds to area of blackboard.

= \frac{\text{Area of Blackboard}}{\text{Area of Poster}} = \frac{\frac{11}{3} }{\frac{8}{9} }

= \frac{33}{8}

Thus, 1 unit area of Poster corresponds to \frac{33}{8}\text{ area of blackboard}

Rzqust [24]2 years ago
3 0
The answer is 143 square feet
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Raj’s bathtub is clogged and is draining at a rate of 1. 5 gallons of water per minute. The table shows that the amount of water
Morgarella [4.7K]

Answer:

Draining rate is at 1.5 gallons per minute

That would be y = 1.5g / x.

From the function or the equation, here is the answer.

The range would be all real numbers such that 0 ≤ y ≤ 40.

Step-by-step explanation:

7 0
2 years ago
The Acme Candy Company claims that​ 60% of the jawbreakers it produces weigh more than 0.4 ounces. Suppose that 800 jawbreakers
vichka [17]

Answer:

Yes, it would be statistically significant

Step-by-step explanation:

The information given are;

The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%

Number of jawbreakers in the sample, n = 800

The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 = \mu _ {\hat p} =p

The formula for the standard deviation of a proportion is \sigma  _{\hat p} =\sqrt{\dfrac{p(1-p)}{n} }

Solving for the standard deviation gives;

\sigma  _{\hat p} =\sqrt{\dfrac{0.6 \cdot (1-0.6)}{800} } = 0.0173

Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4  in the sample of 800 = 800*0.6 = 480

For statistical significance the difference from the mean = 2×\sigma _{\hat p} = 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7

The z-score of 494 jawbreakers is given as follows;

Z=\dfrac{x-\mu _{\hat p} }{\sigma _{\hat p}  }

Z=\dfrac{494-480 }{0.0173  } = 230.94

Therefore, the z-score more than 2 ×\sigma _{\hat p} which is significant.

8 0
2 years ago
A supervisor records the repair cost for 17 randomly selected stereos. A sample mean of $66.34 and standard deviation of $15.22
expeople1 [14]

Answer:

Critical value: T = 1.337

The 80% confidence interval for the mean repair cost for the stereos is between $45.991 and $86.689

Step-by-step explanation:

We have the standard deviation for the sample. So we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 17 - 1 = 16

80% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 16 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.8}{2} = 0.9. So we have T = 1.337, which is the critical value

The margin of error is:

M = T*s = 1.337*15.22 = 20.349

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 66.34 - 20.349 = $45.991

The upper end of the interval is the sample mean added to M. So it is 66.34 + 20.349 = $86.689

The 80% confidence interval for the mean repair cost for the stereos is between $45.991 and $86.689

3 0
2 years ago
check graphically whether the pair of equation 3x-2y+2=0 and 3/2x-y+3=0 is consistent. also find the coordinates of the points w
Sholpan [36]

3x - 2y + 2 = 0 → -2y + 2 = -3x → -2y = -3x - 2 → y = \frac{3}{2}x + 1

\frac{3}{2}x - y + 3 = 0 → -y + 3 = -\frac{3}{2}x → -y = -\frac{3}{2}x - 3 → y = \frac{3}{2}x + 3

These two equations have the same slope but different y-intercepts so they are parallel lines. (aka inconsistent).

Answer: Inconsistent, (0, 1), (0, 3)


3 0
2 years ago
Read 2 more answers
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fgiga [73]

1 cartons of juice = $4.20

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To calculate the percentage, we will do a proportion:

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3.15 : 12.6 = x : 100

To calculate x, we will moltiplicate the ends (where we have known numbers) than divide all per 12.6

So

x = (3.15 * 100) / 12.60 = 315 / 12.6 = 25

So the percentage saving is 25%

6 0
2 years ago
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