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vazorg [7]
1 year ago
5

The value, V(m), of a comic book m must be months after publication has an average rate of change of -0.04 between m=36 and m=60

. Which statement must be true?
A) The value of the comic book decreased by a total of $0.04 between m=36 and m=60

B) The value of the comic book increased by a total of $0.04 between m=36 and m=60

C) The value of the comic book decreased by an average of $0.04 each month between m=36 and m=60

D) The value of the comic book increased by an average of $0.04 each month between m=36 and m=60
Mathematics
1 answer:
Svet_ta [14]1 year ago
7 0

Answer:

A

Step-by-step explanation:

The average is over the months not added each month

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According to the manufacturer, about 26% of sour candy in a package of Sandy's Sours are grape. What is the probability that the
Leto [7]

Answer:


Step-by-step explanation:

We assume that there are 100 sour candies, Thus-  

26 % of candy are grape implies that 26% of 100 candies are grape that is equal to 26

Now remaing candies that are not grape are 100-26 = 74

Based on the rule of multiplication:

P(A ∩ B) = P(A)/ P(B|A)  

 In the beginning, there are 26grape candies, probability of choosing first grape candy =  26C1 = 26

 After the first selection, we replace the selected grape candy so there are still 100 candies in the bag P(B|A) =  100C3 = 100 x 99 x 98 x 97!/3! X 97!

= 50 x 33 x 98

So probability =1/ 50 x 33 x 98 x 26

= 1/4204200



8 0
1 year ago
Read 2 more answers
Consider the midterm and final for a statistics class. Suppose 13% of students earned an A on the midterm. Of those students who
padilas [110]

Answer:

There is a 38.97% probability that this student earned an A on the midterm.

Step-by-step explanation:

The first step is that we have to find the percentage of students who got an A on the final exam.

Suppose 13% students earned an A on the midterm. Of those students who earned an A on the midterm, 47% received an A on the final, and 11% of the students who earned lower than an A on the midterm received an A on the final.

This means that

Of the 13% of students who earned an A on the midterm, 47% received an A on the final. Also, of the 87% who did not earn an A on the midterm, 11% received an A on the final.

So, the percentage of students who got an A on the final exam is

P_{A} = 0.13(0.47) + 0.87(0.11) = 0.1568

To find the probability that this student earned an A on the final test also earned on the midterm, we divide the percentage of students who got an A on both tests by the percentage of students who got an A on the final test.

The percentage of students who got an A on both tests is:

P_{AA} = 0.13(0.47) = 0.0611

The probability that the student also earned an A on the midterm is

P = \frac{P_{AA}}{P_{A}} = \frac{0.0611}{0.1568} = 0.3897

There is a 38.97% probability that this student earned an A on the midterm.

5 0
1 year ago
If 36 is is the dividend and 4 is the divisor then what is the quotient
max2010maxim [7]
Given:
36 is the dividend
4 is the divisor
Since, 4 is the divisor, you are going to want to see how many times 4 can fit into 36 evenly:
4*1=4, 4*2=8, 4*3=12, 4*4=16, 4*5=20, 4*6=24, 4*7=28, 4*9= 36
As you can see above, 4 goes into 36, 9 times evenly:
36/4 = 9
Quotient: 9

I hope this helps!
4 0
1 year ago
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Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skat
BartSMP [9]
Let x be a random variable representing the number of skateboards produced
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b.) P(x ≥ 20,610) = P(z ≥ (20,610 - 20,500)/55) = P(z ≥ 2) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275 = 2.3%

c.) P(x ≤ 20,445) = P(z ≤ (20,445 - 20,500)/55) = P(z ≤ -1) = 1 - P(z ≤ 1) = 1 - 0.84134 = 0.15866 = 15.9%
5 0
2 years ago
Z=25/5 what is the next step in the equation solving sequence.
lbvjy [14]

Answer:

5

Step-by-step explanation:

Z = 25/5

in simplest form........

25/5 = 5/1

so the answer is 5.

3 0
1 year ago
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