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Anika [276]
1 year ago
15

When renting a car two options listed below are given. You need the car for 3 days. How many miles must you travel in order for

option 2 to be the better option? Tell me your variable and what it represents. Then use that variable to set up an equation for each option. Graph each line and use the graph to answer the question. You will need to upload a picture or screenshot of your graphs.
Mathematics
1 answer:
Anastasy [175]1 year ago
4 0

Answer:

it´s b

Step-by-step explanation:

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What is the standard deviation of the market portfolio if the standard deviation of a fully diversified portfolio with a beta of
Nina [5.8K]

Answer:

22.5%

Step-by-step explanation:

let the standard deviation for market portfolio = σₙ

Also let the standard deviation for fully diversified portfolio = σₓ

<u>To calculate fully diversified portfolio</u>

fully diversified portfolio has <em>σₓ = βσₙ</em>

From the given question beta (β) = 1.25

Also standard deviation for market portfolio (σₙ)  = 18% = 0.18

<em>From the equation above,  σₓ = βσₙ </em>= 1.25×0.18 = 0.225

                                                             = 22.5% (converting to percentage)

<em></em>

3 0
1 year ago
A car traveled at a constant speed. The graph shows how far the car traveled, in miles, during a given amount of time, in hours.
snow_tiger [21]

Answer:

Step-by-step explanation:

A car traveled at a constant speed as shown in the graph.

Distance traveled is on the y-axis and duration of travel on the x-axis.

Point A(3.5, 210) shows,

Distance traveled = 210 miles

Time to travel = 3.5 hours

So the point (3.5, 210) shows the distance traveled by the car in 3.5 hours is 210 miles.

Slope of the line = speed of the car = \frac{\text{Distance traveled}}{\text{Time}}

                           = \frac{210}{3.5}

                           = 60 mph

Now we will find the speed of the car at another point B(1, 60).

If the speed of car is same as the point B as of point A, point B will lie on the graph.

Speed of the car at B(1, 60) = \frac{\text{Distance traveled}}{\text{Time}}

                                             = \frac{60}{1}

                                             = 60 mph

Hence, we can say that point B(1, 60) lies on the graph.

8 0
1 year ago
Add the two expressions. 4.6x−3 and −5.3x+9 Enter your answer, in simplified form, in the box. PLEASE ANSWER FAST THIS IS A BIG
Ivan
To add the two expressions, we can write it as:

4.6x-3 + (-5.3x+9)

We can distribute the plus sign (which means just drop the parenthesis in this case):

4.6x-3-5.3x+9

Now, we can simplify by combining like terms:

-0.7x+6
4 0
2 years ago
Read 2 more answers
"I have $225.00 in my account. I can spend all but 20% of that on some new equipment. What is the most that I can afford to spen
oksano4ka [1.4K]
Since you can spend all but 20%, then you can spend the rest, namely the 80%.

whatever% of anything is just (whatever/100) * anything.

therefore, 80% of 225 is then (80/100) * 225, that much.
8 0
2 years ago
Read 2 more answers
(1 point) Let P(t) be the performance level of someone learning a skill as a function of the training time t. The derivative dPd
monitta

Answer:

P(t)=M+Ce^{-kt}

Step-by-step explanation:

Given the differential model

\dfrac{dP}{dt}=k[M-P(t)]

We are required to solve the equation for P(t).

\dfrac{dP}{dt}=kM-kP(t)\\$Add kP(t) to both sides\\\dfrac{dP}{dt}+kP(t)=kM\\$Taking the integrating factor\\e^{\int k dt} =e^{kt}\\$Multiply all through by the integrating factor\\\dfrac{dP}{dt}e^{kt}+kP(t)e^{kt}=kMe^{kt}\\\dfrac{dP}{dt}e^{kt}=kMe^{kt}\\(Pe^{kt})'=kMe^{kt} dt\\$Take the integral of both sides with respect to t\\\int (Pe^{kt})'=\int kMe^{kt} dt\\Pe^{kt}=kM \int e^{kt} dt\\Pe^{kt}=\dfrac{kM}{k} e^{kt} + C_0, C_0$ a constant of integration

Pe^{kt}=Me^{kt} + C\\$Divide both side by e^{kt}\\P(t)=M+Ce^{-kt}\\P(t)=M+Ce^{-kt}\\$Therefore:\\P(t)=M+Ce^{-kt}

4 0
1 year ago
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