Answer:
$12159 per year.
Step-by-step explanation:
If I invest $x each year at the simple interest of 7.5%, then the first $x will grow for 35 years, the second $x will grow for 34 years and so on.
So, the total amount that will grow after 35 years by investing $x at the start of each year at the rate of 7.5% simple interest will be given by

= ![35x + \frac{x \times 7.5}{100} [35 + 34 + 33 + ......... + 1]](https://tex.z-dn.net/?f=35x%20%2B%20%5Cfrac%7Bx%20%5Ctimes%207.5%7D%7B100%7D%20%5B35%20%2B%2034%20%2B%2033%20%2B%20.........%20%2B%201%5D)
= ![35x + \frac{x \times 7.5}{100} [\frac{1}{2} (35) (35 + 1)]](https://tex.z-dn.net/?f=35x%20%2B%20%5Cfrac%7Bx%20%5Ctimes%207.5%7D%7B100%7D%20%5B%5Cfrac%7B1%7D%7B2%7D%20%2835%29%20%2835%20%2B%201%29%5D)
{Since sum of n natural numbers is given by
}
= 35x + 47.25x
= 82.25x
Now, given that the final amount will be i million dollars = $1000000
So, 82.25x = 1000000
⇒ x = $12,158. 05 ≈ $12159
Therefore. I have to invest $12159 per year. (Answer)
Okay so first we need to find how many days are in March and February. March has 31 days and because this year was a leap year February has 29 days.
The next step is to convert days to hours.
March: 31x24=744
February: 29x24=696
Now its time to graph
This is very spread out just to show properly but you could get it smaller haha
317 is the answer you are looking for.
Answer:
The predicted number of wins for a team that has an attendance of 2,100 is 25.49.
Step-by-step explanation:
The regression equation for the relationship between game attendance (in thousands) and the number of wins for baseball teams is as follows:

Here,
<em>y</em> = number of wins
<em>x</em> = attendance (in thousands)
Compute the number of wins for a team that has an attendance of 2,100 as follows:


Thus, the predicted number of wins for a team that has an attendance of 2,100 is 25.49.