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Natalka [10]
1 year ago
12

Name the postulate or theorem you can use to prove ∆ABD ≅ ∆CBD.

Mathematics
2 answers:
lions [1.4K]1 year ago
7 0

Answer:- D) AAS Theorem


Explanation:-

Given :- Δ ADC where ∠A=∠C , ∠ABD=90° which means Bd is an altitude .

⇒∠CBD =90° [∵∠ABD+∠CBD=180° linear pair]

Proof :- In  ∆ABD and ∆CBD.


∠A=∠C [given]..> <u>angle</u>

∠ABD=∠CBD [right angle]..><u> angle</u>

BD=BD [Reflexive property]..><u> </u><u>side</u>

⇒ ∆ABD ≅ ∆CBD [by AAS congruence theorem]

AAS congruence theorem tells that if two angles and one side of a triangle is congruent to the two angles and one side of a triangle then the triangles are congruent.



lozanna [386]1 year ago
5 0
Hey there!

Triangle CBD is congruent to triangle ABD. This means that BD is congruent to BD by reflexive property. You have two congruent angles, and one congruent side. This would be AAS theorem. The answer is D.

I hope this helps!
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