Addends are any of the numbers added together in an equation.
The only time their grouping would matter would be if there were parentheses used to alter the normal Order of Operations.
For ex:
2 - (8 + 3) here, the 8 and 3 have to be grouped together before doing the subtraction.
Any addition problem without parentheses can be used for one where the grouping doesn't matter
Answer:
i) (0, 2) and (1, 2), ii) (0.333, 1.333) and (1, 2).
Step-by-step explanation:
i) Let be 
, if 
, which is equivalent to the following system of equations:
Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0, 2) and (1, 2)
ii) Let be , if 
, which is equivalent to the following system of equations:
Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0.333, 1.333) and (1, 2)
Answer:
the cyclists rode at 35 mph
Step-by-step explanation:
Assuming that the cyclists stopped, and accelerated instantaneously at the same speed than before but in opposite direction , then
distance= speed*time
since the cyclists and the train reaches the end of the tunnel at the same time and denoting L as the length of the tunnel :
time = distance covered by cyclists / speed of cyclists = distance covered by train / speed of the train
thus denoting v as the speed of the cyclists :
7/8*L / v = L / 40 mph
v = 7/8 * 40 mph = 35 mph
v= 35 mph
thus the cyclists rode at 35 mph
Answer: at 11:54
Step-by-step explanation:
Let's define the 10:30 as our t = 0 min.
We know that Train A stops every 12 mins, and Train B stops every 14 mins, they will stop at the same time in the least common multiple of 12 and 14.
To find the least common multiple of two numbers, we must do:
LCM(a,b) = a*b/GCD(a,b)
Where GCD(a, b) is the greatest common divisor of a and b.
In this case the only common divisior of 12 and 14 is 2.
So we have:
LCM(12, 14) = 12*14/2 = 84.
Then the both trains will stop 84 minutes after 10:30
one hour has 60 mins, so we can write 84 minutes as:
1 hour and 24 minutes = 1:24
Then they will stop at the same time at 10:30 + 1:24 = 11:54
