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vagabundo [1.1K]
1 year ago
13

Which is the rate of change for the interval between 3 and 6 on the x-axis? 0-2

Mathematics
1 answer:
Hunter-Best [27]1 year ago
8 0

Image is missing, so i have attached it.

Answer:

Rate of change = 2

Step-by-step explanation:

From the image attached, we are given a parabola which opens upwards with many points marked on the curve.

We are asked to find the rate of change for the interval between 3 and 6 on the x axis.

Now, rate of change of any function f(x) from a to b is given by the formula ;

Rate of change = [f(b) - f(a)]/(b - a)

For this question, a = 3 and b = 6

f(3) is simply the y-value when x is 3. On the graph, f(3) = -2

Similarly,f(6) = 4

Thus;

Rate of change = [4 - (-2)]/(6 - 3)

Rate of change = 6/3

Rate of change = 2

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2 years ago
b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
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First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

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<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

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⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

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8 0
2 years ago
If q is inversely proportional to r squared and q=30 when r=3, find r when q=1.2
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r = \sqrt{10.8 /1.2} = 3

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