We know that
Half-life is modeled by the formula
An=A0*(0.5)<span>^[t/h)]
where
An----------> </span>is the amount remaining after a time t
A0----------> is the initial quantity
t------------> is the time
h------------> is the half-life of the decaying quantity
in this problem
h=1601 years
A0=50 g
An=?
t=100 years
An=A0*(0.5)^[t/h)]---------> An=50*(0.5)^[100/1601)]-----> 47.88 gr
the answer is 47.88 g
X - 9 + 2wx = y Add 9 to both sides
x + 2wx = y + 9 Factor out the x
x (1 + 2w) = y + 9 Divide both sides by (1 + 2w)
x = (y + 9) / (1 + 2w)
C. $122.10. You take 20, then take 10 percent of that to find the second hour's earnings (which is $22), then you take 10% of that number to find the next hour's earnings, and so on and so on until you reach the 5th hour. When you add all the values up, you get $122.10.
Part A: Linear function
explanation:
The table for the value of the two cars with time are given as follows;
Years Car 1 Car 2
1 18,500 18,500
2 17,390 17,500
3 16,500 16,346.6
Plotting the give data, we have;
From the plot of the data, the function that can be used to describe the values of both cars after a fixed number of years is a linear function
Hope this helps a bit
