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marishachu [46]
2 years ago
9

A random generated list of numbers from 0 to 4 is being used to simulate an event, with the numbers 3 and 4 representing a succe

ss. what is the estimated probability of a success?
A. 60%
B. 40%
C. 25%
D. 75%
Mathematics
1 answer:
Sloan [31]2 years ago
6 0
Since there are 5 numbers 0-4 and there are 2 numbers that is a success. The probability is 2/5 or 40% or B.
You might be interested in
A small island is 4 miles from the nearest point P on the straight shoreline of a large lake. If a woman on the island can row a
True [87]

Answer:

a) t(x)  = [ √ (4)² + (x)²]/ 4    +   7/5  - x/5

b) x = 0,97 miles

c) t (min)  = 1,24 hours

Step-by-step explanation: See Annex

Figure in annex shows a clear description of the situation

Let  x be distance in miles between point P and where boat lands

A woman has to row  a distance L

L = √ (4)² + (x)²

and the part to get to the town (which she has to walk)

d = ( 7 -  x)

But we are required to give time as a function of x

distance   =  speed * time     ⇒   t  = distance / speed

Therefore

t(x)  = [ √ (4)² + (x)²]/ 4   +   ( 7  -  x  ) / 5

t(x)  = [ √ (4)² + (x)²]/ 4    +   7/5  - x/5

Taking derivatives both sides of the equation

t¨(x)   = ( 2x)*4 / 16√ (4)² + (x)²]   -  5/25  

t¨(x)   = x/  2√ (4)² + (x)²]  - 1/5

t¨(x)   = 0      x/  2√ (4)² + (x)²]  - 1/5   =  0

[ 5 x  -  2√ (4)² + (x)²]  =  0       ⇒   5x    =  2√ (4)² + (x)²]   or

   25 x² =  4  (  4 +   x²)

   25 x² = 16  +   8x²

  17x²   =   16

  x²  =   16/17      

   x²   =  0,941

  x = 0,97 miles  

And the distance walking to get to town

d =  7  -  x       d =   7  -  0,97

d  = 6,03 miles

The least travel time  is   t(x)  = [ √ (4)² + (x)²]/ 4    +   7/5  - x/5  

t (min)  =  √ 16 +  0,94) /4   +  1,4  - 0,97/5

t (min)  = 1,03  +  1,4  - 0,194

t (min)  = 1,24 hours

7 0
1 year ago
A random sample of 50 units is drawn from a production process every half hour. the true fraction of nonconforming products manu
Naya [18.7K]

solution:

The probability mass function for binomial distribution is,

 

Where,

X=0,1,2,3,…..; q=1-p

find the probability that (p∧ ≤ 0.06) , substitute the values of sample units (n) , and the probability of nonconformities (p) in the probability mass function of binomial distribution.

Consider x   to be the number of non-conformities. It follows a binomial distribution with n   being 50 and p  being 0.03. That is,

binomial (50,0.02)

Also, the estimate of the true probability is,

p∧  = x/50

The probability mass function for binomial distribution is,

 

Where,

X=0,1,2,3,…..; q=1-p

The calculation is obtained as

P(p^ ≤ 0.06) = p(x/20 ≤ 0.06)

         = 50cx ₓ (0.03)x ₓ (1-0.03)50-x  

=    (50c0 ₓ (0.03)0 ₓ (1-0.03)50-0 + 50c1(0.03)1 ₓ (1-0.03)50-1 + 50c2 ₓ (0.03)2 ₓ (1-0.03)50-2 +50c3 ₓ      (0.03)3 ₓ (1- 0.03)50-3 )

=(   ₓ (0.03)0 ₓ (1-0.03)50-0 +  ₓ (0.03)1 ₓ (1-0.03)50-1 +   ₓ (0.03)2 ₓ (1-0.03)50-2   ₓ (0.03)3 ₓ (1-0.03)50-3 )



5 0
1 year ago
You have just timed a person doing a hair cut for the first time. It took 50 minutes. What unit improvement factor learning curv
Sladkaya [172]

Answer: C. 70 percent

Step-by-step explanation:

Given, Time for the first unit = 50 minutes

Time for the second unit = 35 minutes

The unit improvement factor learning curve = (The time for the second unit) ÷ (time for the first unit) x 100.

So, The unit improvement factor learning curve  = 35÷ 50 × 100 = 70 percent.

Hence, the correct option is "C. 70 percent".

3 0
1 year ago
Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4
german

Answer:

range is  between 55.5 to 64.5

Step-by-step explanation:

Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4.5 inches

68% is 1 standard deviation from mean

To get the range of 1 standard deviation we add and subtract standard deviation from mean

mean = 60

standard deviation = 4.5

60 - 4.5= 55.5

60+4.5 = 64.5

1 standard deviation is between 55.5 to 64.5

That is 68% range is  between 55.5 to 64.5

8 0
2 years ago
Solve the following addition and subtraction problems. a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam b. 5 sq.km 95 ha 8,994 sq.m + 11 sq.
kipiarov [429]
As a general rule to solve the problem we are going to transform all values to the lower unit.  
a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam
  3,000 m 900 m 90 m 19 m + 7,000 m 70 m = 4,009 + 7,070 = 11,079 m 
  b. 5 sq.km 95 ha 8,994 sq.m + 11 sq. km. 11 ha 9,010 sq. m.
  5,000,000 sq m 95,0000 sq m 8,994 sq m + 11,000,000 sq m 110,000 sq
9,010 sq m
  5,103,994 sq m + 11,119,010 sq m = 16,223,004 sq m 
 c. 44 m – 5 dm
  44 m - 0.5 m = 43.5 m 
 d. 73 km 47 hm 2 dam - 11 km 55 hm

  73,000 m 4,700 m 20 m - 11,000 m 5,500 m 
77,720 m - 16,500 m = 61,220 m
5 0
1 year ago
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