Ask question

Ask question

All categories

Zielflug [23.3K]

2 years ago

11

Hamlet cut a piece of paper into a rhombus to use as part of a costume. The piece of paper is shown below.*Picture not drawn to

scaleWhat is the area of the piece of paper? A. 44 square inches B. 60.5 square inches C. 105.6 square inches D. 121 square inches

1 answer:

ehidna [41]2 years ago

6 0

The answer is letter “B”

You might be interested in

Jana is ordering a list of numbers from least to greatest. StartRoot 7 squared EndRoot, StartRoot 7 EndRoot, Four-fifths, StartR

makvit [3.9K]

Answer:

The answer is D

Step-by-step explanation:

$\frac{4}{5}$ = 0.8

$\sqrt{7}$ = 2.64

2.64 > 0.8 because 2 is a whole number while 0.8 is a decimal

8 0

2 years ago

Read 2 more answers

Geoffrey is evaluating the expression StartFraction (negative 3) cubed (2 Superscript 6 Baseline) Over (Negative 3) Superscript

makkiz [27]

The mathematical expression does not seem clear but I have made an attempt to make sense of what is implied.

Answer:

<em>a</em> = 4, <em>b</em> = 2, <em>c</em> = 16, <em>d</em> = 9

Step-by-step explanation:

$\dfrac{(-3)^3(2^6)}{(-3)^5(2^2)} = \dfrac{(2)^a}{(-3)^b} = \dfrac{c}{d}$

Solving the first part of the question by indices,

$\dfrac{(-3)^3(2^6)}{(-3)^5(2^2)} = (-3)^{3-5}(2)^{6-2} = (-3)^{-2}(2)^{4} = \dfrac{(2)^4}{(-3)^2}$

Comparing the rightmost term with the second term in the question,

<em>a</em> = 4, <em>b</em> = 2

Solving on,

$\dfrac{(2)^4}{(-3)^2} = \dfrac{(2)\times(2)\times(2)\times(2)}{(-3)\times(-3)} = \dfrac{16}{9}$

Comparing with the final term in the question,

<em>c</em> = 16 and <em>d</em> = 9

Therefore,

<em>a</em> = 4, <em>b</em> = 2, <em>c</em> = 16, <em>d</em> = 9

3 0

2 years ago

Read 2 more answers

Emery looks out their apartment window to the building across the way. The building isknown to be 42 feet tall. The angle of dep

Amanda [17]

Answer:

$x=44.5ft$

Step-by-step explanation:

From the question we are told that:

Height $h=42ft$

Angle of depression $\theta=27\textdegree$

Angle of Elevation $\alpha=23 \textdegree$

Generally the equation for the vertical distance between Emery's distance x and the bottom of the building is mathematically given by

Since the angle of depression and elevation are given as

27 and 23 respectively

Therefore

Emery's view of the 42 ft building is

$\gamma=23+27$

$\gamma=50 \textdegree$

Therefore Emery's distance x to the base of the building h' is

$h'=\frac{27}{50}*42$

$h'=22.68ft$

Generally the Trigonometric equation for Emery's distance x is mathematically given by

$x=\frac{h'}{tan\theta}$

$x=\frac{22.68}{tan 27}$

$x=44.5ft$

6 0

1 year ago

The Reverend Henry Whitehead was skeptical of John Snow's conclusion about the Broad Street pump. After the Broad Street cholera

Mamont248 [21]

Answer:

The main reason it was important to study this group was:

1) If Whitehead had found that many people had drunk water from the Broad Street pump and not caught cholera, that would have been evidence against Snow's hypothesis.

Step-by-step explanation:

But Dr. John Snow was able to convince many councillors who ensured that the pump handle was removed from the Broad Street pump. Within a few days of this removal, the cholera epidemic ended. This step proved that Dr. Snow was right from the beginning. The pump handle was the means that the cholera epidemic was being spread from one person to another within Broad Street area, since many usually fetch water from the pump.

4 0

2 years ago

An anthropologist finds that a prehistoric bone contains less than 8.1% of the amount of Carbon-14 the bones would have containe

stealth61 [152]

Answer:

20,944 years

Step-by-step explanation:

The formula you use for this type of decay problem is the one that uses the decay constant as opposed to the half life in years. We are given the k value of .00012. If we don't know how much carbon was in the bones when the person was alive, it would be safer to say that when he was alive he had 100% of his carbon. What's left then is 8.1%. Because the 8.1% is left over from 100% after t years, we don't need to worry about converting that percent into a decimal. We can use the 8.1. Here's the formula:

$N(t)=N_{0} e^{-kt}$

where N(t) is the amount left over after the decay occurs, $N_{0}$ is the initial amount, -k is the constant of decay (it's negative cuz decay is a taking away from as opposed to a giving to) and t is the time in years. Filling in accordingly,

$8.1=100e^{-.00012t}$

Begin by dividing the 100 on both sides to get

$.081=e^{-.00012t}$

Now take the natural log of both sides. Since the base of a natual log is e, natural logs and e "undo" each other, much like taking the square root of a squared number.

ln(.081)= -.00012t

Take the natual log of .081 on your calculator to get

-2.513306124 = -.00012t

Now divide both sides by -.00012 to get t = 20,944 years

4 0

2 years ago