The area of a square is expressed as the length of the side to the power of two, A = s^2. We were given the area of the enlarged photo which is 256 in^2. Also, it was stated that the length of the enlarged photo is the length of the original photo plus ten inches. So, from these statements we can make an equation to solve for x which represents the length of the original photo.
A = s^2
where s = (x+10)
A = (x+10)^2 = 256
Solving for x,
x= 6 in.
The dimensions of the original photo is 6 x 6.
Answer:
X=7 ST=11 RT=17
Step-by-step explanation:
RT=RS+ST. RS= 2(7)-8. ST=11
X+10=2x-8+11. =14-8=6. RT= x+10
X+10=2x+3. RS=6. 7+10=17
10=x+3. RT=17
X=7
Answer:

Step-by-step explanation:
We want to find the sum of

We can rewrite this as

This becomes;

Recall that;

This implies that;

Combine like terms:

Answer:
The revenue for Granton location is 175 thousand dollars
Step-by-step explanation:
Given
Cedarton 121
Rimber 189
Linton 147
Mean = 158
Required
Revenue for Granton location.
To calculate the revenue for Granton location, we make use of mean formula.
Mean is calculated by Summation of Observation divided by number of observations.
Since Granton location is unknown; Let it be represented by letter G.
So, the summation of observation becomes 121 + 189 + 147 + G
Summation = 457 + G
The number of observations = 4
Recall that Mean = Summation ÷ Number
By substituting 158 for mean, 457 + G for summation and 4 for number, we have
158 = (457 + G) ÷ 4
158 = ¼(457 + G)
Multiply both sides by 4
4 * 158 = = 4 * ¼(457 + G)
632 = 457 + G
Make G the subject of formula
G = 632 - 457
G = 175
Hence, the revenue for Granton location is 175 thousand dollars
Answer:
The graph is shown below.
Step-by-step explanation:
Given:
The inequality of a line to graph is given as:

In order to graph it, we first make the 'inequality' sign to 'equal to' sign. This gives,

Now, we plot this line on a graph. The given line is of the form:
Where, 'm' is the slope and 'b' is the y-intercept.
So, for the line
, 
The y-intercept is at (0, -3).
In order to draw the line correctly we find another point. Let the 'y' value be 0.
Now, 
So, the point is (3, 0).
Now, we mark these points and draw a line passing through these two points.
Now, consider the line inequality
. The 'y' value is less than
. So, the solution region will be region below the line and excluding all the points on the line. So, we draw a broken line and shade the region below it.
The graph is shown below.