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FinnZ [79.3K]
2 years ago
9

Question 1 Unsaved In a poll of students at the basketball championship, 82% of the students say that basketball is better than

football. (a) Explain why it is not a valid conclusion to say that basketball is more popular than football at the school. (b) Suggest a better method of determining which sport is more popular.
Mathematics
1 answer:
STALIN [3.7K]2 years ago
7 0
A. It is not a valid conclusion that basketball is more popular at the school because they are surveying at a basketball game.

B. A school wide poll. 
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Se distribuyen 400 bolsas en tres urnas sabiendo que la primera tiene 80 menos que la segunda y esta tiene 60 menos que la terce
laiz [17]

Answer:

Primeras urnas = 60 bolsas

Segundas urnas = 140 bolsas

Terceras urnas = 200 bolsas

Step-by-step explanation:

Deje que las urnas se representen de la siguiente manera

Primeras urnas = a

Segundas urnas = b

Terceras urnas = c

Se nos dice en la pregunta

400 bolsas se distribuyen en tres urnas

Por lo tanto,

a + b + c = 400 bolsas ......... Ecuación 1

Por la pregunta sabemos que

1) El primero tiene 80 menos que el segundo

a = b - 80

2) Y este segundo tiene 60 menos que el tercero

b = c - 60

Por tanto, c = b + 60

Por lo tanto, sustituimos b - 80 por ayb + 60 por c en la Ecuación 1

a + b + c = 400 bolsas ......... Ecuación 1

b - 80 + b + b + 60 = 400 bolsas

Recopilar términos similares

b + b + b - 80 + 60 = 400 bolsas

3b = 400 + 80 - 60

3b = 420

b = 420/3

b = 140 bolsas

Por lo tanto, el número de bolsas en la segunda urna = 140 bolsas

Dado que a = b - 80

a = 140 bolsas - 80

a = 60 bolsas

Por lo tanto, el número de bolsas en la primera urna = 60 bolsas

Dado que c = b + 60

b = 140 bolsas

c = 140 + 60

c = 200 bolsas.

El número de bolsas en las terceras urnas = 200 bolsas.

4 0
2 years ago
The sides of a square are three to the power of two sevenths inches long. What is the area of the square? (
____ [38]

Answer:

Step-by-step explanation:

The side of the square = 3^2/7

Use the law of exponents . If the power is a fraction, that means it is

3^2/7 = 3^2 x 1/7 = 7√9

To find the area you multiply this by itself.

This gives you 1.87...

Hope this helps

8 0
2 years ago
A member of a student team playing an interactive marketing game received the fol- lowing computer output when studying the rela
nirvana33 [79]

Answer:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

Step-by-step explanation:

Let's suppose that we have the following linear model:

y= \beta_o +\beta_1 X

Where Y is the dependent variable and X the independent variable. \beta_0 represent the intercept and \beta_1 the slope.  

In order to estimate the coefficients \beta_0 ,\beta_1 we can use least squares procedure.  

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: \beta_1 = 0

Alternative hypothesis: \beta_1 \neq 0

Or in other words we want to check is our slope is significant (X have an effect in the Y variable )

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal  

The significance level assumed on this case is \alpha=0.05

The standard error for the slope is given by this formula:

SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}

Th degrees of freedom for a linear regression is given by df=n-2 since we need to estimate the value for the slope and the intercept.  

In order to test the hypothesis the statistic is given by:

t=\frac{\hat \beta_1}{SE_{\beta_1}}

The p value on this case would be given by:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

3 0
2 years ago
Andrea has a yard shaped like parallelogram ABCD. The garden area, parallelogram EFGB, has an area of 105 ft2004-05-02-04-00_fil
Lynna [10]

The area of a parallelogram is simply calculated using the formula:

A = b * h

Where,

b = length of the base = 45 ft

h = height which is perpendicular to the base = 21 ft

Using the formula, we calculate the total area of the yard.

A = b* h

A = 45 ft * 21 ft

A = 945 ft^2

Now we don’t want to sod the Garden area for the most obvious reason. The garden has an Area of 105 ft^2, we subtract this to the total area giving us,

Area to sod = 945 ft^2 – 105ft^2

<span>Area to sod = 840 ft^2</span>

5 0
2 years ago
Which of the number(s) below are potential roots of the function? p(x) = x4 + 22x2 – 16x – 12
Neporo4naja [7]

Complete question is;

Which of the number(s) below are potential roots of the function? p(x) = x⁴ + 22x² – 16x – 12

A) ±6

B) ±1

C) ±3

D) ±8

Answer:

Options A, B & C: ±6, ±1, ±3

Step-by-step explanation:

We are given the polynomial;

p(x) = x⁴ + 22x² – 16x – 12

Now, the potential roots will be all the rational numbers equivalent of p/q.

Where;

p are the factors of the constant term of the polynomial

q are the factors of the leading coefficient of the polynomial

Now, in the given polynomial, the constant term is seen as -12 while leading coefficient is 1 which is the coefficient of x⁴.

We know that factors of 12 are any of:

±1, ±2, ±3, ±4, ±6 and ±12

While possible factors of 1 is just ±1.

Thus, all the potential roots of the polynomial function are;

±1, ±2, ±3, ±4, ±6 and ±12

From the options given, option A, B & C could be the potential roots.

6 0
2 years ago
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