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Natasha2012 [34]
2 years ago
10

Susan works as a hostess where she makes $8.75 per hour. She also babysits and earns $10.00 per hour. Last week she made $165.00

. If she worked 6hour more as a hostess than she did babysitting, how many hours did she babysit last week?
Mathematics
2 answers:
True [87]2 years ago
5 0

Answer:

6 hours as a babysitter and 12 hours as a hostess

Sholpan [36]2 years ago
3 0

Answer:

She worked 11.25 hours

Step-by-step explanation:

8.75×6 = 52.5

165.00 - 52.5 = 112.5

112.5 ÷ 10 = 11.25

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Using a ruler and a compass,Jimmy constructs a square inscribed within a circle. He starts by drawing a circle with a center at
lana66690 [7]

Answer:

He set the compass on a, with the width slightly wider than the distance to o and drew an arc above and below o. He then set the compass on b, without changing the width on the compass and did the same thing. True

He drew a line through where the arc pairs intersected and then labeled the points where this line crossed the top and bottom of the original circle. True

He set the compass on o, with the width slightly wider than the distance to b, and he drew a slightly larger circle around the original circle. False

He used the points that were marked along the circumference of the original circle as the vertices for the square. True

Step-by-step explanation:

Performance matters test perhaps?

5 0
2 years ago
Maggie has exactly $20 to buy decorations for the dance. Streamers cost $2 per roll and balloons are $1.50 per package. Which se
IgorC [24]

Answer:

streamers are closest to her budget.

Step-by-step explanation:

because if you want to buy balloons then you would have to buy 13.3 3 is infinite, but if you bought streamers then you would only buy 10.

6 0
2 years ago
An empty can weighs 30 grams. The weight of the same can filled with liquid is 47.3 grams. Which equation could be used to find
Alika [10]

Answer:

w = y - x is the equation to find w

Where,

w = Weight of the liquid

x = Weight of the empty can

y = Weight of the can with liquid

Step-by-step explanation:

Let

Weight of the empty can = x

Weight of the liquid = w

Weight of the can with liquid = x + w = y

x= 30 grams

w = ?

y= 47.3 grams

y = x + w

w = y - x

= 47.3 - 30

= 17.3

w= 17.3 grams

Therefore, the weight of the liquid is 17 .3 grams

3 0
2 years ago
Determine whether the sets have a subset relationship. R = {right triangles} O = {obtuse triangles} a) R and O are disjoint. b)
DerKrebs [107]

Answer:

f

Step-by-step explanation:

A right angled triangle has one angle equal to 90°

an obtuse angle triangle has one angle greater tan 90°

a) An o and right-angled triangle btuse angled triangle can have one angle equal.

b) R and O are not equivalent by definition

c)  subset of R and Oare not all triangles as R and O are categories of all triangles. R and O are subset of all triangles

d) Acute triangles have all acute angles. So subset of R and O can't be all acute traingles

e) All triangles with two acute angles are may or may not have third angle as obtuse angle or 90° angle

f) none of the above

5 0
2 years ago
A sample of bacteria is being eradicated by an experimental procedure. The population is following a pattern of exponential deca
77julia77 [94]

Answer:

There will be 50 bacteria remaining after 28 minutes.

Step-by-step explanation:

The exponential decay equation is

N=N_0e^{-rt}

N= Number of bacteria after t minutes.

N_0 = Initial number of bacteria when t=0.

r= Rate of decay per minute

t= time is in minute.

The sample begins with 500 bacteria and after 11 minutes there are 200 bacteria.

N=200

N_0 = 500

t=11 minutes

r=?

N=N_0e^{-rt}

\therefore 200=500e^{-11r}

\Rightarrow e^{-11r}=\frac{200}{500}

Taking ln both sides

\Rightarrow ln| e^{-11r}|=ln|\frac{2}{5}|

\Rightarrow {-11r}=ln|\frac{2}{5}|

\Rightarrow r}=\frac{ln|\frac{2}{5}|}{-11}

To find the time when there will be 50 bacteria remaining, we plug N=50, N_0= 500 and  r}=\frac{ln|\frac{2}{5}|}{-11} in exponential decay equation.

50=500e^{-\frac{ln|\frac25|}{-11}.t}

\Rightarrow \frac{50}{500}=e^{\frac{ln|\frac25|}{11}.t}

Taking ln both sides

\Rightarrow ln|\frac{50}{500}|=ln|e^{\frac{ln|\frac25|}{11}.t}|

\Rightarrow ln|\frac{1}{10}|={\frac{ln|\frac25|}{11}.t}

\Rightarrow t= \frac{ln|\frac{1}{10}|}{\frac{ln|\frac25|}{11}.}

\Rightarrow t= \frac{11\times ln|\frac{1}{10}|}{{ln|\frac25|}}

\Rightarrow t\approx 28 minutes

There will be 50 bacteria remaining after 28 minutes.

3 0
2 years ago
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