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Zarrin [17]
1 year ago
9

The Cozy Car Company created a new model of car especially for Japan and Vietnam, which they start shipping to both countries at

the same time.The company had shipped 222 of that model of car to Japan by the end of the first month, and the cumulative total of cars they've shipped triples each month.The company had shipped 555 of that model of car to Vietnam by the end of the first month, and the cumulative total of cars they've shipped increases by 111111 cars each month.In which month will the cumulative number of cars of that model shipped to Japan first exceed the cumulative total shipped to Vietnam?

Mathematics
1 answer:
leonid [27]1 year ago
4 0
We assume you intend that cars shipped to Japan are modeled by
  j(n) = 2·3^(n-1)
and that those shipped to Vietnam are modeled by
  v(n) = 5 + 11·(n-1)

The value of j(n) will exceed the value of v(n) in month 4.

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kipiarov [429]
As a general rule to solve the problem we are going to transform all values to the lower unit.  
a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam
  3,000 m 900 m 90 m 19 m + 7,000 m 70 m = 4,009 + 7,070 = 11,079 m 
  b. 5 sq.km 95 ha 8,994 sq.m + 11 sq. km. 11 ha 9,010 sq. m.
  5,000,000 sq m 95,0000 sq m 8,994 sq m + 11,000,000 sq m 110,000 sq
9,010 sq m
  5,103,994 sq m + 11,119,010 sq m = 16,223,004 sq m 
 c. 44 m – 5 dm
  44 m - 0.5 m = 43.5 m 
 d. 73 km 47 hm 2 dam - 11 km 55 hm

  73,000 m 4,700 m 20 m - 11,000 m 5,500 m 
77,720 m - 16,500 m = 61,220 m
5 0
2 years ago
The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci
Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that n = 300 and \pi = \frac{10}{300} = 0.033

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532

The correct answer is

(0.0128, 0.0532)

4 0
1 year ago
Complete the statements for the graph of f(x) = |x|. The domain of the function is . The range of the function is . The graph is
ioda

Answer:

Domain of f(x): All real numbers

Range of f(x):  f(x) \geq0 ---> [0, ∞)

The graph is over the interval (0, ∞)

Step-by-step explanation:

The function absolute value of x that is written: f(x) = | x | assigns only positive values to f(x) at any value of x.

For example, if for f(x) = | x | we make

f(-23) = | -23 | then the absolute value of x "transforms" the number -23 to +23.

Then f(-23) = | -23 | = 23

This means that f(x) will be positive for any value of x.

Therefore, we can conclude that:

Domain of f(x): All real numbers

Range of f(x):  f(x) \geq0 ---> [0, ∞)

The graph is over the interval (0, ∞)

5 0
2 years ago
Read 2 more answers
The grade point average in an econometrics examination was normally distributed with a mean of 75. in a sample of 10 percent of
podryga [215]
<span>No. From the data provided you can not determine what the standard deviation is. In order to determine the standard deviation you need the actual grades not just a mean.</span>
8 0
2 years ago
Zach keeps his pet chameleon Pinky in a terrarium with the dimensions shown below. There are 3 inches of sand in the bottom of t
VMariaS [17]
The correct question is
<span>Zach keeps his pet chameleon Pinky in a terrarium with the dimensions 8 x 20. There are three inches of sand in the bottom of the terrarium. Zach gets a new terrarium that is larger. The base of the new terrarium is 10 x 24 inches. Zach moved the existing sand to the new terrarium. How deep will the sand be in the new terrarium?
</span>

Step 1
find the volume of sand
volume of sand=8*20*3------------>Volume of sand=480 in³

Volume of sand in the new terrarium=10*24*h
where h------------> is the deep in the new terrarium
remember that the volume of sand is the same
so
10*24*h=480----------> h=480/(10*24)-----------> h=2 in

the answer is 2 in
6 0
2 years ago
Read 2 more answers
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