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tamaranim1 [39]
2 years ago
10

In a recent​ year, 304 of the approximately​ 300,000,000 people in the United States were struck by lightning. Estimate the prob

ability that a randomly selected person in the United States will be struck by lightning this year.
Mathematics
2 answers:
umka2103 [35]2 years ago
6 0

Answer:

\frac{19}{18,750,000}=0.0000010133333333

Step-by-step explanation:

We have been given that in a recent​ year, 304 of the approximately​ 300,000,000 people in the United States were struck by lightning.

\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Number of possible outcomes}}

\text{P( A randomly selected person in the United States will be struck by lightning this year)}=\frac{304}{300,000,000}

\text{P( A randomly selected person in the United States will be struck by lightning this year)}=\frac{19}{18,750,000}

\text{P( A randomly selected person in the United States will be struck by lightning this year)}=0.0000010133333333

Therefore, the probability that a randomly selected person in the United States will be struck by lightning this year is \frac{19}{18,750,000}=0.0000010133333333.

Alexus [3.1K]2 years ago
3 0

Answer:

19/18750000

Step-by-step explanation:

Total number of people  in the United States = 300,000,000

Number of people in the United States who got  struck by lightning = 304

To find: probability that a randomly selected person in the United States will be struck by lightning this year

Solution:

Probability that a randomly selected person in the United States will be struck by lightning this year = Number of people in the United States who got  struck by lightning / Total number of people  in the United States

= 304/300,000,000

= 19/18750000

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7. Ella and her family normally pay $165 per
Anna [14]

Answer:

$99

Step-by-step explanation:

Cost of electricity per year= $165

Tax per month= 5%

Amount of tax paid per month= 5% of $165

= 0.05 × 165

= $8.25

Ella's family pays $8.25 tax per month

There are 12 months in 1 year

Ella's family will pay Ina year = $8.25 × 12

= $99

Ella's family will pay $99 tax for an entire year

4 0
1 year ago
Herky was given the following system of equations to solve. 3 x minus 2 y = 17. x minus 3 y = 1.
ioda

Answer:

(7, 2 )

Step-by-step explanation:

Given the 2 equations

3x - 2y = 17 → (1)

x - 3y = 1 → (2)

Rearrange (2) expressing x in terms of y by adding 3y to both sides

x = 1 + 3y → (3)

Substitute x = 1 + 3y in (1)

3(1 + 3y) - 2y = 17 ← distribute and simplify left side

3 + 9y - 2y = 17

3 + 7y = 17 ( subtract 3 from both sides )

7y = 14 ( divide both sides by 7 )

y = 2

Substitute y = 2 into (3) for corresponding value of x

x = 1 + 3(2) = 1 + 6 = 7

Solution is (7, 2 )

5 0
2 years ago
Read 2 more answers
24. ABCDE and PQRST are regular pentagons.
SIZIF [17.4K]

Answer:

126°

Step-by-step explanation:

In quadrilateral DSRC, SR || DC (given)

AP = BQ = CR = DS = ET (given)

\therefore CR bisects \angle DCB

\therefore m\angle DCR=\frac{108\degree}{2}

(108\degree is the measure of an angle of pentagon)

\therefore m\angle DCR=54\degree

\because m\angle DCR + m\angle SRC=180\degree

(Measure of interior angles on the same side of transversal)

\therefore 54\degree + m\angle SRC=180\degree

\therefore  m\angle SRC=180\degree- 54\degree

\therefore  m\angle SRC=126\degree

3 0
2 years ago
A wheat farmer cuts down the stalks of wheat and gathers them in 200 piles. The 200 gathered piles will be put on a truck. The t
denpristay [2]

Answer:

Check the explanation

Step-by-step explanation:

We want to estimate the total weight of grain on the field based on the data on a simple random sample of 5 piles out of 200. The population and sample sizes are N=200 & n=5 respectively.

1) Let Y_1,Y_2,...,Y_{200} be the weight of grain in the 200 piles and y_1,y_2,...,y_{5} be the weights of grain in the pile from the simple random sample.

We know, the sample mean is an unbiased estimator of the population mean. Therefore,

\widehat{\mu}=\overline{y}=\frac{1}{5}\sum_{i=1}^{5}y_i=\frac{1}{5}(3.3+4.1+4.7+5.9+4.5)=4.5

where \mu is the mean weight of grain for all the 200 piles.

Hence, the total grain weight of the population is

\widehat{Y}=Y_1+Y_2+...+Y_{200}

=200\times \widehat{\mu}\: \: \: =200\times 4.5\: \: \: =900\, lbs

2) To calculate a bound on the error of estimates, we need to find the sample standard deviation.

The sample standard deviation is

 S=\sqrt{\frac{1}{5-1}\sum_{i=1}^{5}(y_i-\overline{y})^2}\: \: \: =0.9486

Then, the standard error of \widehat{Y} is

\sigma_{\widehat{Y}} =\sqrt{\frac{N^2S^2}{n}\bigg(\frac{N-n}{N}\bigg)}\: \: \:=83.785

Hence, a 95% bound on the error of estimates is

[\pm z_{0.025}\times \sigma_{\widehat{Y}}]\: \: \: =[\pm 1.96\times 83.875]\: \: \: =[\pm 164.395]

3) Let x_1,x_2,...,x_5 denotes the total weight of the sampled piles.

Mean total weight of the sampled piles is

\overline{x}=\frac{1}{5}\sum_{i=1}^{5}x_i=45

The sample ratio is

r=\frac{\overline{y}}{\overline{x}}=\frac{4.5}{45}=0.1 , this is also the estimate of the population ratio R=\frac{\overline{Y}}{\overline{X}} .

Therefore, the estimated total weight of grain in the population using ratio estimator is

\widehat{Y}_R\: \: =r\times 8800\: \: =0.1\times 8800\: \: =880\, lbs

4) The variance of the ratio estimator is

var(r)=\frac{N-n}{N}\frac{1}{n}\frac{1}{\mu_x^2}\frac{\sum_{i=1}^{5}(y_i-rx_i)^2}{n-1}   , where \mu_x=8800/200=44lbs

=\frac{200-5}{200}\, \frac{1}{5}\: \frac{1}{44^2}\, \frac{0.2}{5-1}=0.000005

Hence, the standard error of the estimate of the total population is

\sigma_R=\sqrt{X^2 \: var(r)}\: \: \: =\sqrt{8800^2\times 0.000005}\: \: \:=21.556

Hence, a 95% bound on the error of estimates is

[\pm z_{0.025}\times \sigma_{R}]\: \: \: =[\pm 1.96\times 21.556]\: \: \: =[\pm 42.25]

8 0
2 years ago
Read 2 more answers
Two numbers are randomly selected on a number line numbered from 1 to 9. Match each scenario to its probability.
Talja [164]

Answer:

1/9; 4/9; 1/12; 1/6

Step-by-step explanation:

the probability that both numbers are greater than 6 if the same number can be chosen twice--> 3/9 * 3/9 = 1/9

the probability that both numbers are less than 7 if the same number can be chosen twice --> 6/9 * 6/9 = 4/9

the probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice --> 3/9 * 2/8 = 1/12

the probability that both numbers are even numbers if the same numbers cannot be chosen twice --> 4/9 * 3/8 = 1/6

5 0
2 years ago
Read 2 more answers
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