Carl is wondering if the train he is riding home from school will leave early, on time, or late. The probabilities are

In a certain region, the number of highway accidents increased by 20% over the four years period. How many accidents were there

erma4kov [3.2K]

Equation:

a = 5120

r = 1 + .2 = 1 . 2

f (n ) = 5120 * 1 . 2^n - 1

N = 4 years

f ( 4 ) 5120 * 1 . 2^4 - 1

5120 * 1 . 2^3

We want to know, The number of Highway Accidents in Four Years.

Answer: 8,847 Highway Accidents total:

Hope that helps!!!!!!!!!!! : )

7 0

2 years ago

A quality control engineer tests the quality of produced computers. suppose that 5% of computers have defects, and defects occur

11111nata11111 [884]

(a) 0.059582148 probability of exactly 3 defective out of 20

(b) 0.98598125 probability that at least 5 need to be tested to find 2 defective.

(a) For exactly 3 defective computers, we need to find the calculate the probability of 3 defective computers with 17 good computers, and then multiply by the number of ways we could arrange those computers. So

0.05^3 * (1 - 0.05)^(20-3) * 20! / (3!(20-3)!)

= 0.05^3 * 0.95^17 * 20! / (3!17!)

= 0.05^3 * 0.95^17 * 20*19*18*17! / (3!17!)

= 0.05^3 * 0.95^17 * 20*19*18 / (1*2*3)

= 0.05^3 * 0.95^17 * 20*19*(2*3*3) / (2*3)

= 0.05^3 * 0.95^17 * 20*19*3

= 0.000125* 0.418120335 * 1140

= 0.059582148

(b) For this problem, let's recast the problem into "What's the probability of having only 0 or 1 defective computers out of 4?" After all, if at most 1 defective computers have been found, then a fifth computer would need to be tested in order to attempt to find another defective computer. So the probability of getting 0 defective computers out of 4 is (1-0.05)^4 = 0.95^4 = 0.81450625.

The probability of getting exactly 1 defective computer out of 4 is 0.05*(1-0.05)^3*4!/(1!(4-1)!)

= 0.05*0.95^3*24/(1!3!)

= 0.05*0.857375*24/6

= 0.171475

So the probability of getting only 0 or 1 defective computers out of the 1st 4 is 0.81450625 + 0.171475 = 0.98598125 which is also the probability that at least 5 computers need to be tested.

3 0

2 years ago

It is 1 1/4 miles from Ahmed’s house to school. How far does Ahmed’s travel in 5 days walking to school and back

Sauron [17]

Ahmed travel $12\frac{1}{2}$ miles in 5 days walking to school and back.

Step-by-step explanation:

Distance from house to school = $1\frac{1}{4}$ miles

Distance from school to house = $1\frac{1}{4}$ miles

Total distance in 1 day = $1\frac{1}{4}+1\frac{1}{4}=\frac{5}{4}+\frac{5}{4}$

Total distance in 1 day = $\frac{5+5}{4}=\frac{10}{4}$

Distance traveled in 5 days = $5*\frac{10}{4}=\frac{50}{4}$

Distance traveled in 5 days = $\frac{25}{2}=12\frac{1}{2}$

Ahmed travel $12\frac{1}{2}$ miles in 5 days walking to school and back.

Keywords: fraction, addition

Learn more about fractions at:

#LearnwithBrainly

5 0

2 years ago

Given: The coordinates of triangle PQR are P(0, 0), Q(2a, 0), and R(2b, 2c).

masha68 [24]

Answer:

The line containing the midpoints of two sides of a triangle is parallel to the third side ⇒ proved down

Step-by-step explanation:

* Lets revise the rules of the midpoint and the slope to prove the

problem

- The slope of a line whose endpoints are (x1 , y1) and (x2 , y2) is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The mid-point of a line whose endpoints are (x1 , y1) and (x2 , y2) is

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

* Lets solve the problem

- PQR is a triangle of vertices P (0 , 0) , Q (2a , 0) , R (2b , 2c)

- Lets find the mid-poits of PQ called A

∵ Point P is (x1 , y1) and point Q is (x2 , y2)

∴ x1 = 0 , x2 = 2a and y1 = 0 , y2 = 0

∵ A is the mid-point of PQ

∴ $A=(\frac{0+2a}{2},\frac{0+0}{2})=(\frac{2a}{2},\frac{0}{2})=(a,0)$

- Lets find the mid-poits of PR which called B

∵ Point P is (x1 , y1) and point R is (x2 , y2)

∴ x1 = 0 , x2 = 2b and y1 = 0 , y2 = 2c

∵ B is the mid-point of PR

∴ $B=(\frac{0+2b}{2},\frac{0+2c}{2})=(\frac{2b}{2},\frac{2c}{2})=(b,c)$

- The parallel line have equal slopes, so lets find the slopes of AB and

QR to prove that they have same slopes then they are parallel

# Slope of AB

∵ Point A is (x1 , y1) and point B is (x2 , y2)

∵ Point A = (a , 0) and point B = (b , c)

∴ x1 = a , x2 = b and y1 = 0 and y2 = c

∴ The slope of AB is $m=\frac{c-0}{b-a}=\frac{c}{b-a}$

# Slope of QR

∵ Point Q is (x1 , y1) and point R is (x2 , y2)

∵ Point Q = (2a , 0) and point R = (2b , 2c)

∴ x1 = 2a , x2 = 2b and y1 = 0 and y2 = 2c

∴ The slope of AB is $m=\frac{2c-0}{2b-2a}=\frac{2c}{2(b-c)}=\frac{c}{b-a}$

∵ The slopes of AB and QR are equal

∴ AB // QR

∵ AB is the line containing the midpoints of PQ and PR of Δ PQR

∵ QR is the third side of the triangle

∴ The line containing the midpoints of two sides of a triangle is parallel

to the third side

6 0

2 years ago

The expression 10,785(1.0275)x represents the amount of money in an investment account with interest that compounds annually for

Ksivusya [100]

Answer: It shows the formula for "Amount" using the compound interest formula.

Step-by-step explanation:

Since we have given that

The expression :

$10785(1.0275)^x$

So, it can be rewritten as

$10785(1+0.0275)^x\\\\=10785(1+\dfrac{2.75}{100})^x$

Here, initial investment = $ 10785

Rate of interest = 2.75%

Number of years = x

So, it shows the formula for "Amount" using the compound interest formula.

3 0

2 years ago