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2 years ago

Carl is wondering if the train he is riding home from school will leave early, on time, or late. The probabilities are

Mathematics

1 answer:

crimeas [40]2 years ago

5 0

Answer:

[train leaves early] ---- [train leaves on time]------[train leaves late]

Step-by-step explanation:

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An isosceles triangle has base 6 and height 11. find the maximum possible area of a rectangle that can be placed inside the tria

svetoff [14.1K]

The area of the triangle is 33

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2 years ago

If the quantity 4 times x times y cubed plus 8 times x squared times y to the fifth power all over 2 times x times y squared is

MA_775_DIABLO [31]

$\dfrac{4xy^3 + 8x^2y^5 }{2xy^2}$

$= \dfrac{4xy^3(1+2xy^2)}{2xy}$

$= 2y^2(1 + 2xy^2)$

$= 2y^2 + 4xy^4$

Answer: a = 1, b 2, c = 1, d = 4

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2 years ago

Colleen compared the ratios 3:8 and One-half. Her work is shown below. Write the ratios as fractions: Three-eighths and One-half

labwork [276]

This question is Incomplete

Complete Question

Colleen compared the ratios 3:8 and 1/2.

Her work is shown below.

Write the ratios as fractions: 3/8 and 1/8 Compare the numerators: 3 > 1 Write the correct statement: 3/8 > 1/2

Where did Colleen make her first mistake?

A. The common denominator should be 4 rather than 8

B. The numerators are compared incorrectly.

C. The fraction 1/2 should have been rewritten as 6/8

D. The fraction 1/2 should have been rewritten as 4/8.

Answer:

D. The fraction 1/2 should have been rewritten as 4/8.

Step-by-step explanation:

Colleen compared the ratios 3:8 and 1/2.

Step 1

Write the ratios as fractions: 3/8 and 1/2

Step 2

Compare the numerators: 3 > 1

Step 3

Compare the denominators 8 >2

Write the correct statement:

3/8 > 4/8

Therefore, D. The fraction 1/2 should have been rewritten as 4/8.

5 0

2 years ago

E varies directly with the square root of C. If E=40 when C=25, find: C when E = 10.4

sukhopar [10]

Answer: C = 1.69

Step-by-step explanation:

E is proportional to √C

To remove proportionality, introduce a constant (k).

E = k × √C

From question,

E = 40 and C = 25

So,

40 = k ×√25

40 = k × 5

k = 8

Now,

C = ?

E = 10.4

k = 8

E = k × √C

10.4 = 8 × √C

10.4 / 8 = √C

( 10.4 / 8 ) ^ 2 = C

C = 1.69

6 0

2 years ago

Read 2 more answers

You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the

Makovka662 [10]

Answer:

The total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 0.5 years is $ 309.00.

The total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 1 year is $ 318.27.

Step-by-step explanation:

a) How much will you have at the middle of the first year?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

where

Principle = P

Annual rate = r

Compound = n

Time = (t in years)

A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

substituting the values

$A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}$

$A=300\cdot \frac{2.06}{2}$

$A=\frac{618}{2}$

$A=309$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

where

Principle = P

Annual rate = r

Compound = n

Time = (t in years)

A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

so substituting the values

$A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}$

$A=300\cdot \frac{2.06^2}{2^2}$

$A=318.27$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 1 year is $ 318.27.

3 0

2 years ago