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lutik1710 [3]
2 years ago
9

Luther evaluated 23 as 9 and Wade evaluated 32 as 9. Are both students correct? Explain why or why not.

Mathematics
2 answers:
CaHeK987 [17]2 years ago
7 0
The answer 

let  A= 2^3 and B=3^2

the main formula is as following:

a^n = axaxax ....xa (n times), for all n upper than or equal 1
 for example 
a^3 = a x ax a

in our case 
 A= 2^3 = 2x2x2= 4x2 =8
B=3^2 = 3x 3= 9
so, Luther's evaluation was wrong, by contrast <span>Wade evaluated 32 as 9 correctly

</span>
Artist 52 [7]2 years ago
6 0

Answer:

Sample Response: The two powers are not equal. Wade is correct, but Luther misinterpreted 2 to the power of 3 as 2 factors of 3. He switched the base and exponent. Luther’s value should be 2 times 2 times 2, which is 8.

Step-by-step explanation: Hope this helps leave a 5 star pls :)

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Janisa researched fast-growing industries and occupations, while Rylan researched industries and occupations that have the highe
topjm [15]

Answer:

<u>Janisa found that home health care is the fastest-growing occupation and services for the elderly is the fastest growing industry, while Rylan found that elementary and secondary school teaching are the occupations with the highest employment and retail sales is the industry with the highest employment. </u>

<u>Explanation:</u>

We make this conclusion because when we look at all the other options none matches the definition of occupations and industries. However, if Janisa found that home health care is the fastest-growing<u> occupation</u>, and then services for the elderly are the fastest growing <u>industry,</u> it matches what we know an industry and occupation mean.

While, if Rylan found that elementary and secondary school teaching are the occupations with the highest employment, it matches an example of occupation also, and if he discovers that retail sales is the industry with the highest employment it also falls under industry types.

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2 years ago
Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
babunello [35]

For this case, the first thing we are going to do is write the generic equation of motion for the vertical axis.

We have then:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

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  • <em>vo: initial speed </em>
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For the first body:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second body:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

By the time both bodies have the same height we have:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rewriting we have:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

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6 0
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Step-by-step explanation:

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