Ask question

Ask question

All categories

2 years ago

14

The tabletop below is made from right triangles, each the same size. Your company charges $0.20 per square inch for sanding the

tabletop. Which of the following is closest to the tabletop’s area, in square inches28 1/4"*4+20*4=a. 550 b.950 c.2,800 d.3,950 e.5,600

1 answer:

Roman55 [17]2 years ago

3 0

Answer: The correct answer is c.

Step-by-step explanation:

You take the area of the square which is 20x20 = 400.

There is 5 squares 400x5 = 2000

There is 4 triangles--which is 1/2 the area of 1 square (In this case).

One triangle = 200

200x4 = 800

2000 + 800 = 2800

You might be interested in

Write the expression n.n.p.p.r.r.r

borishaifa [10]

Answer:

2n.2p.3r

Step-by-step explanation:

idk

7 0

2 years ago

A study is conducted to determine whether a new cancer drug increases the mean survival time by at least 30 days for a certain t

anygoal [31]

Answer:

H0: The new cancer drug increases the mean survival time by 30 days

Ha: The new cancer drug increases the mean survival time by 30 or more than 30 days.

If fail to reject H0 (the null hypothesis), the conclusion is that the new cancer drug increases the mean survival time by 30 days.

Step-by-step explanation:

The null hypothesis is a statement from a population parameter which is either rejected or accepted (fail to reject) upon testing. It is expressed using the equality sign.

The alternate hypothesis is also a statement from a population parameter which negates the null hypothesis and is accepted if the null hypothesis is rejected. It is expressed using any of the inequality signs.

The test is a two-tailed test because the alternate hypothesis is expressed using more than or equal to.

If I fail to reject H0, it means the test statistic falls within the region bounded by the critical values.

It would therefore be concluded that the new cancer drug increases the mean survival time by 30 days.

8 0

2 years ago

A machine produces parts that are either defect free (90%), slightly defective (3%), or obviously defective (7%). Prior to shipm

AURORKA [14]

Answer:

(a) 0.0686

(b) 0.9984

(c) 0.0016

Step-by-step explanation:

Given that a machine produces parts that are either defect free (90%), slightly defective (3%), or obviously defective (7%).

Let A, B, and C be the events of defect-free, slightly defective, and the defective parts produced by the machine.

So, from the given data:

P(A)=0.90, P(B)=0.03, and P(C)=0.07.

Let E be the event that the part is disregarded by the inspection machine.

As a part is incorrectly identified as defective and discarded 2% of the time that a defect free part is input.

So, $P\left(\frac{E}{A}\right)=0.02$

Now, from the conditional probability,

$P\left(\frac{E}{A}\right)=\frac{P(E\cap A)}{P(A)}$

$\Rightarrow P(E\cap A)=P\left(\frac{E}{A}\right)\times P(A)$

$\Rightarrow P(E\cap A)=0.02\times 0.90=0.018\cdots(i)$

This is the probability of disregarding the defect-free parts by inspection machine.

Similarly,

$P\left(\frac{E}{A}\right)=0.40$

and $\Rightarrow P(E\cap B)=0.40\times 0.03=0.012\cdots(ii)$

This is the probability of disregarding the partially defective parts by inspection machine.

$P\left(\frac{E}{A}\right)=0.98$

and $\Rightarrow P(E\cap C)=0.98\times 0.07=0.0686\cdots(iii)$

This is the probability of disregarding the defective parts by inspection machine.

(a) The total probability that a part is marked as defective and discarded by the automatic inspection machine

$=P(E\cap C)$

$= 0.0686$ [from equation (iii)]

(b) The total probability that the parts produced get disregarded by the inspection machine,

$P(E)=P(E\cap A)+P(E\cap B)+P(E\cap C)$

$\Rightarrow P(E)=0.018+0.012+0.0686$

$\Rightarrow P(E)=0.0986$

So, the total probability that the part produced get shipped

$=1-P(E)=1-0.0986=0.9014$

The probability that the part is good (either defect free or slightly defective)

$=\left(P(A)-P(E\cap A)\right)+\left(P(B)-P(E\cap B)\right)$

$=(0.9-0.018)+(0.03-0.012)$

$=0.9$

So, the probability that a part is 'good' (either defect free or slightly defective) given that it makes it through the inspection machine and gets shipped

$=\frac{\text{Probabilily that shipped part is 'good'}}{\text{Probability of total shipped parts}}$

$=\frac{0.9}{0.9014}$

$=0.9984$

(c) The probability that the 'bad' (defective} parts get shipped

=1- the probability that the 'good' parts get shipped

=1-0.9984

=0.0016

5 0

2 years ago

Josh works for a construction company that uses 150 pounds of gravel for each driveway they pour. He can buy a dump truck load w

Pavlova-9 [17]

Answer:

Josh should by the dump truck with 30,000 pounds of gravel in it

Step-by-step explanation:

the easiest way to find this out is divide 30,000 and 2,500 by 150 and if the answer is a whole number, then you know that is the correct answer.

30,000/150 = 200

2,500/150 = 16.6666666666666

May I have brainliest please? :)

5 0

2 years ago

The fuel cost per hour for running a ship is approximately one half the cube of the speed (measured in knots) plus additional fi

andrezito [222]

Answer:

6 knots

Step-by-step explanation:

Let the speed be v knots

then time taken to cover 500 M = 500 / v hrs

fuel consumption /hr = 216 + 0.5v^3

let F be the fuel consumption for trip

= [500/v][216 + 0.5v^3]

= 500[216/v + 0.5v^2]

dF/dv = 500[ - 216/v^2 + v]

d^2F/d^2v = 500[432/v^3 + 1] , i.e. +ve

so setting dF/dv will give a minima

500[ -216/v^2 + v] = 0

or v = 216/v^2

or v^3 = 216

solving, we get v = [216]^(1/3) = 6 knots

7 0

2 years ago