Point R and point T have same x coordinate so their distance is by y axis.
Ty-Ry=2.4-1.3=1.1
So the distance between two points is 1.1
To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
Hope I helped :)
Given that PQ and RS intersect to form four right angles, then they form an angle of 90 degrees, this implies that:
if the meet at point O,
then;
∠POR=∠POS=∠QOS=∠ROQ=90°
Therefore the correct statement is:
PQ is perpendicular to RS
that is to mean:
PQ⊥RS
The answer is C.
The answer is "MS and QS". Trust me I just took the test and made a 90
Answer:
11 adult tickets
Step-by-step explanation:
I guess you want the number of adult tickets sold.
That is 20% of 55
= 0.20*55
= 11 (answer)
