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EleoNora [17]
2 years ago
10

Top fuel dragster cars can accelerate from rest down a quarter mile track (400 meters) in under 4 seconds. Assuming constant acc

eleration, what would the acceleration of a dragster be if it sped down a track in exactly 4 seconds?
Mathematics
1 answer:
lawyer [7]2 years ago
3 0

Answer:

Its acceleration will be 25m/s^2

Step-by-step explanation:

Distance the drag star moved from rest =400meters

Time taken =4 seconds

Speed= velocity= distance/time= 400m/4 s=100m/s

Acceleration at time 4 seconds will be;

Acceleration = Velocity/time=100/4=25m/s^2

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Answer: A-meaning first chart


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Find a right triangle that has legs with your irrational Lengths and a hypotenuse with a rational Length
cluponka [151]

gg easy


the legs of a triangle are related as a^2+b^2=c^2 wehre a, b, and c are the legs and the hypotonuse of a triangle respectively


let's find some stuff

one easy way is to find a rational value for c find values of a and b

lets pick c=5

a^2+b^2=5^2

a^2+b^2=25

now split up 25 into 2 things that don't have rational square roots

if we say a^2=19 and b^2=6 then we get

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4 0
2 years ago
A coordinate grid with 2 lines. The first line is labeled y equals negative StartFraction 7 over 4 EndFraction x plus StartFract
KengaRu [80]

Answer:

1) (2.2, -1.4)

2) (1.33, 1)

Step-by-step explanation:

Question 1)

Two lines, with their corresponding equations are given and we have to find the solution to the system of equations.

The given lines are:

Equation of Line 1:

y=\frac{-7}{4}x+\frac{5}{2}

This line passes through the points: (0, 2.5) , (2.2, -1.4)

Equation of Line 2:

y=\frac{3}{4}x-3

This line passes through the points (0, -3) , (2.2, -1.4)

By looking at the graph/given data we have to find the solution of these linear equations.

Remember that the solution of linear equations is an ordered pair, through which both the lines pass i.e. the point at which both the given lines intersect is the solution of the linear equations.

From the given data we can see that both the lines pass through one common point, (2.2, -1.4). Since, both lines pass through this point, this means this is the point of intersection of the lines and hence there solution.

So, the answer to this questions is (2.2, -1.4)

Question 2)

The given equations are:

y = 1.5x - 1                                        Equation 1

y = 1                                                  Equation 2

We can solve these equations by method of substitution.

Substituting the value of y from Equation 2, in Equation 1, we get:

1 = 1.5x - 1

1 + 1 = 1.5x

2 = 1.5x

x = 2/1.5

x = 1.33

y = 1

Thus, the solution of the given linear equations is (1.33, 1)

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The organizers of a talent show have budgeted $1800 to buy souvenir clothing to sell at the event. They can buy shirts for $10 e
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Let s represent number of shirts and h represent number of hats.

We have been given that the organizers of a talent show have budgeted $1800 to buy souvenir clothing to sell at the event. They can buy shirts for $10 each and hats for $8 each.

The cost of s shirts would be 10s and cost of h hats would be 8h. The cost of s shirts and h hats should be less than or equal to 1800. We can represent this information in an inequality as:

10s+8h\leq 1800

We are also told that organizers plan to buy at least 5 times as many shirts as hats. This means that number of shirts should be greater than or equal to 5 times hats. We can represent this information in an inequality as:

s\geq 5h

Therefore, the second inequality should be s\geq 5h and option C is the correct choice.

6 0
2 years ago
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