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andrew11 [14]
2 years ago
12

ther a Point Is Part of the Solution Decide whether each point is a solution to the system. y<=3x+4 and y<=3x-2 (0, –2) (5

, 0) (3, 13)
Mathematics
1 answer:
frosja888 [35]2 years ago
3 0

Answer:

(5,0) is the only solution out of those points

Step-by-step explanation:

If you graph the 2 inequalities you'll notice the point (0,-2) falls on the dotted line, since the line is dotted this can not be a solution as a dotted line entails that anything on that line is not a solution, for the point (3,13) it doesn't fall in a solution for either inequality due to what I just stated, the point (5,0) on the other hand falls in the domain and range of both inequalities.

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Sandy evaluated the expression below. (negative 2) cubed (6 minus 3) minus 5 (2 + 3) = (negative 2) cubed (3) minus 5 (5) = 8 (3
nasty-shy [4]

Answer:

should be - 8

Step-by-step explanation:

-2*-2=4 4*-2=-8

4 0
2 years ago
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The ratio of Melanie's allowance to Jacob's allowance is 4.1 to 20.5. If Jacob gets $5.00, how much allowance does Melanie get?
BartSMP [9]

If Melanie get's 4.10$, then Jacob get's 20.50$.

We can divide to get the unit rate:

20.50 ÷ 4.10 = 5

This means that if Jacob gets 5$, then Melanie will get 1$.

So in this case, Melanie get's 1$.

6 0
2 years ago
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Which of the following statements must be true in order for the line represented by the equation y = mx + b to have a negative x
inn [45]
First option: <span>The signs of the values of m and b are the same.</span>
6 0
2 years ago
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A bacon cheeseburger at a popular fast food restaurant contains 2,070mg of sodium, which is 86% of the recommended daily amount.
svp [43]
2,070mg 86%
— = —
? mg 100%

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5 0
2 years ago
Consider the discussion in our Devore reading in this unit involving an important distinction between mean and median that uses
Levart [38]

Answer:

Step-by-step explanation:

A trimmed mean is a method of averaging that removes a small designated percentage of the largest and smallest values before calculating the mean. After removing the specified observations, the trimmed mean is found using a standard arithmetic averaging formula. The use of a trimmed mean helps eliminate the influence of data points on the tails that may unfairly affect the traditional mean.

trimmed means provide a better estimation of the location of the bulk of the observations than the mean when sampling from asymmetric distributions;

the standard error of the trimmed mean is less affected by outliers and asymmetry than the mean, so that tests using trimmed means can have more power than tests using the mean.

if we use a trimmed mean in an inferential test , we make inferences about the population trimmed mean, not the population mean. The same is true for the median or any other measure of central tendency.

I can imagine saying the skewness is such-and-such, but that's mostly a side-effect of a few outliers, the fact that the 5% trimmed skewness is such-and-such.

I don't think that trimmed skewness or kurtosis is very much used in practice, partly because

If the skewness and kurtosis are highly dependent on outliers, they are not necessarily useful measures, and trimming arbitrarily solves that problem by ignoring it.

Problems with inconvenient distribution shapes are often best solved by working on a transformed scale.

There can be better ways of measuring or more generally assessing skewness and kurtosis, such as the method above or L-moments. As a skewness measure (mean ? median) / SD is easy to think about yet often neglected; it can be very useful, not least because it is bounded within [?1,1][?1,1].

i expect to see the optimum point in that process at some value between the mean and median.

3 0
2 years ago
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