Ask question

Ask question

All categories

Dahasolnce [82]

2 years ago

6

suppose you buy a CD for $250 that earns 3% APR and is compounded quarterly. The CD matures in 5 years, assume that is funds are

withdrawn before the CD matures. The early withdrawal fee is 3 months interest. what is the early withdrawal fee on the account?

2 answers:

ollegr [7]2 years ago

4 0

I got $1.88 For apex

vredina [299]2 years ago

3 0

Answer:

1.88

Step-by-step explanation:

a.p.e.x

You might be interested in

Aramp is 17 feet long, rises 8 feet above the floor, and covers a horizontal distance of 15 feet, as shown in the figure.

bonufazy [111]

Answer:

The ratio of Tan B is

$\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}$

OR

$\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}$

Step-by-step explanation:

In Right Angle Triangle ABC

angle C = 90°

AB = Ramp = 17 feet

BC =Horizontal distance = 15 feet

AC = Height from floor = 8 feet

To Find:

Ratio of Tan B = ?

Solution:

In Right Angle Triangle ABC By Tangent Identity we have

$\tan B= \dfrac{\textrm{side opposite to angle B}}{\textrm{side adjacent to angle B}}$

Substituting the given values we get

$\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}$

OR

$\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}$

5 0

2 years ago

Farid is baking muffins, The recipe calls for 3/4 cup of sugar for a full batch. Farid is making 1/2 of a batch. Write an expres

Tems11 [23]

Answer:

y = 3/8x

or

3/8 cups of sugar for every 1/2 batch of muffins

Step-by-step explanation:

Since we are only making 1/2 of the full batch of muffins, we only need to use 1/2 the cups of sugar:

$\frac{3}{4} (\frac{1}{2} )= \frac{3}{8}$ cups of sugar.

8 0

2 years ago

Read 2 more answers

Which of the following are possible explicit formulas for the nth term of the constant velocity sequence below? Check all that a

oksano4ka [1.4K]

We have an arithmetic progression:
Nth=an
an=a₁+(n-1)d
a₁ is the first term.
n=number of terms.
d=common difference

10,17,24,31...
a₁=10
d=a₂-a₁=17-10=7

Therefore:
Nth=an
an=a₁+(n-1)d
an=10+(n-1)7
an=10+7n-7
an=7n+3.

Therefore: the formula for the nth is, an=a+(n-1), in this case; an=7n+3,

To check:
a₁=7*1+3=10
a₂=7*2+3=17
a₃=7*3+3=24
a₄=7*4+3=31
a₅=7*5+3=38.......

8 0

2 years ago

Let L be the line with parametric equations x=2+t, y=1-t, z=1+3t.Let v=(1,2,0).Find vectors w1 and w2 such that v= w1 + w2, and

charle [14.2K]

Answer:

w1 = (-1/11, 1/11, -3/11)

w2 = (12/11, 21/11, 3/11)

Step-by-step explanation:

Direction ratio of w1 = Direction ratio of L (because parallel) = K+(1, -1, 3)

Let <a,b,c> be direction ratio of w2.

Then, <a,b,c>. <1,-1,3> = 0

a-b+3c = 0

v = w1 + w2

(1, 2, 0) = k(1, -1, 3) + (a, b, c)

a + k = 1

b - K = 2

c - 3k = 0

Solving 4 equations, a = 12/11, b= 21/11, c = 3/11, k=-1/11

So, w1 = -1/11(1, -1 ,3) = (-1/11, 1/11, -3/11)

w2 = (12/11, 21/11, 3/11)

6 0

1 year ago

A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

$Area = 128$

Let the dimension of the paper be x and y;

Such that:

$Length = x$

$Width = y$

So:

$Area = x * y$

Substitute 128 for Area

$128 = x * y$

Make x the subject

$x = \frac{128}{y}$

When 1 inch margin is at top and bottom

The length becomes:

$Length = x + 1 + 1$

$Length = x + 2$

When 2 inch margin is at both sides

The width becomes:

$Width = y + 2 + 2$

$Width = y + 4$

The New Area (A) is then calculated as:

$A = (x + 2) * (y + 4)$

Substitute $\frac{128}{y}$ for x

$A = (\frac{128}{y} + 2) * (y + 4)$

Open Brackets

$A = 128 + \frac{512}{y} + 2y + 8$

Collect Like Terms

$A = \frac{512}{y} + 2y + 8+128$

$A = \frac{512}{y} + 2y + 136$

$A= 512y^{-1} + 2y + 136$

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

$A' = -512y^{-2} + 2$

Set

$A' = 0$

This gives:

$0 = -512y^{-2} + 2$

Collect Like Terms

$512y^{-2} = 2$

Multiply through by $y^2$

$y^2 * 512y^{-2} = 2 * y^2$

$512 = 2y^2$

Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

$y = 16$

Recall that:

$x = \frac{128}{y}$

$x = \frac{128}{16}$

$x = 8$

Recall that the new dimensions are:

$Length = x + 2$

$Width = y + 4$

So:

$Length = 8 + 2$

$Length = 10$

$Width = 16 + 4$

$Width = 20$

To double-check;

Differentiate A'

$A' = -512y^{-2} + 2$

$A" = -2 * -512y^{-3}$

$A" = 1024y^{-3}$

$A" = \frac{1024}{y^3}$

The above value is:

$A" = \frac{1024}{y^3} > 0$

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0

1 year ago