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Dahasolnce [82]

2 years ago

6

suppose you buy a CD for $250 that earns 3% APR and is compounded quarterly. The CD matures in 5 years, assume that is funds are

withdrawn before the CD matures. The early withdrawal fee is 3 months interest. what is the early withdrawal fee on the account?

2 answers:

ollegr [7]2 years ago

4 0

I got $1.88 For apex

vredina [299]2 years ago

3 0

Answer:

1.88

Step-by-step explanation:

a.p.e.x

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An irregular parallelogram rotates 360° about the midpoint of its diagonal. How many times does the image of the parallelogram c

Helga [31]

2 times it will coincide

6 0

2 years ago

Which test point holds true for y − 2x ≤ 1?

CaHeK987 [17]

So in order to find the correct answer, we can just easily plug in the values to check which ordered pair matches the given inequality above. So based on my solutions, the correct answer would be the last pair.
<span> y − 2x ≤ 1
0 - 2(5)</span> ≤ 1
0-10 ≤ 1
-10 ≤ 1
Hope this answer helps.

3 0

2 years ago

Suppose the cost C(x), to build a football stadium of x thousand square feet is approximated by C(x) = 7,250,000/ x + 60 . How m

Luba_88 [7]

Answer:

Step-by-step explanation:

Suppose the cost C(x), to build a football stadium of x thousand square feet is approximated by C(x) = 7,250,000/x + 60. Given the function, we can substitute values for x to determine the cost of a particular size of stadium or we can substitute values for C(x) to determine the number of square feet.

if the cost of the stadium was $8,000, the, we would determine the size of the stadium, x by substituting x $8,000 for C(x). It becomes

8000 = 7250,000/x + 60

8000 - 60 = 7250000/x

7940 = 7250000/x

7940x = 7250000

x = 7250000/ 7940

x = 913 ft^2

7 0

2 years ago

How long will it take before twenty percent of our 1,000-gram sample of uranium-235 has decayed? [See Section 6.6 Example 13] Th

horsena [70]

Answer:

From what I can see of the problem, you CANNOT solve for the half-life of U 235 AND then solve for the length of time to determine the 20% decay.

U-235 half-life is 704,000,000 years. (Wikipedia)

The elapsed time formula = half-life * [log (Beginning Amount / ending amount) / log 2]

elapsed time = 7.04 x 10^8 * [log (100 % / 80%) / log 2]

elapsed time =7.04 x 10^8 * [log (1.25) / .30103]

elapsed time =7.04 x 10^8 * [0.096910 / .30103]

elapsed time = 7.04 x 10^8 * 0.321928047

elapsed time = 226,637,000 years

Step-by-step explanation:

8 0

2 years ago

Suppose 1000 people enter a chess tournament. Use a rooted tree model of the tournament to determine how many games must be play

Vlada [557]

Answer: 999 games

Step-by-step explanation:

There are many ways to illustrate the rooted tree model to calculate the number of games that must be played until only one player is left who has not lost.

We could go about this manually. Though this would be somewhat tedious, I have done it and attached it to this answer. Note that when the number of players is odd, an extra game has to be played to ensure that all entrants at that round of the tournament have played at least one game at that round. Note that there is no limit on the number of games a player can play; the only condition is that a player is eliminated once the player loses.

The sum of the figures in the third column is 999.

We could also use the formula for rooted trees to calculate the number of games that would be played.

$i=\frac{l - 1}{m - 1}$

where i is the number of "internal nodes," which represents the number of games played for an "<em>m</em>-ary" tree, which is the number of players involved in each game and l is known as "the number of leaves," in this case, the number of players.

The number of players is 1000 and each game involves 2 players. Therefore, the number of games played, i, is given by

$i=\frac{l - 1}{m - 1} = i=\frac{1000 - 1}{2 - 1} = \frac{999}{1} =999$

7 0

1 year ago