Answer:
A)2/y
B)2/(y-1)
C)2/(y-2)
D)2/(y-3)
Step-by-step explanation:
Based on the information available :
Let the total number of marbles = y
Number of blue marbles = 2
Game ends when Hayley draws a blue marble.
NB: Marble is drawn without replacement
A.) P(game ends on first draw) = (number of blue marbles) / total number of marbles
P(game ends on first draw) = 2/y
B.) P(game ends on second draw) :
If game doesn't end on first draw, then no blue marble was drawn on the first pick
P(game ends on second draw) = 2/(y-1)
C.)P(game ends on third draw) = 2 / (y-2)
D.)P(game ends on fourth draw) = 2/(y-3)
There isn't enough information to solve the remaining problems
