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Serggg [28]
2 years ago
6

A parallelogram has an area of 42cm^2. What would the area be if the base was one-third as long and the height was twice as long

?
Mathematics
1 answer:
AnnZ [28]2 years ago
7 0
Area of a parallelogram is the product of its base and height.

Let the base be "b" and height be "h". So we can write:

Area  = bh = 42 cm²

After the change, base is one-third. So the new length of the base will be: b/3 
After the change, height is twice as long. So the new height will be :  2h

Area after the change = \frac{b}{3}* 2h=  \frac{2}{3}  bh
Using the value of bh from equation above we get:

Area after the change = \frac{2}{3}  * 42 = 28 cm²

So the area of new parallelogram will be 28 cm²
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2 years ago
what is a correct first step in solving the inequality –4(3 – 5x)≥ –6x 9? –12 – 20x ≤ –6x 9 –12 – 20x ≥ –6x 9 –12 20x ≤ –6x 9 –1
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<span>The answer is -12 + 20x ≥ –6x 9. The inequality is –4(3 – 5x)≥ –6x 9. The first step is to multiply factors on the left side. The intermediary steps are: (-4)*(3) - (-4)*(5x) ≥ –6x 9. -12 - (-20x) ≥ –6x 9. So, the first step will be: -12 + 20x ≥ –6x 9.</span>
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