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2 years ago

Which is greater 9000cm or 2 km?

Mathematics

1 answer:

satela [25.4K]2 years ago

6 0

Convert 2 km into cm

1 km = 100,000 cm

2 km = 200,000 cm

therefore 9,000 cm is greater

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You have just timed a person doing a hair cut for the first time. It took 50 minutes. What unit improvement factor learning curv

Sladkaya [172]

Answer: C. 70 percent

Step-by-step explanation:

Given, Time for the first unit = 50 minutes

Time for the second unit = 35 minutes

The unit improvement factor learning curve = (The time for the second unit) ÷ (time for the first unit) x 100.

So, The unit improvement factor learning curve = 35÷ 50 × 100 = 70 percent.

Hence, the correct option is "C. 70 percent".

3 0

2 years ago

5.63x10^-5 in standard form

NemiM [27]

Answer:

the correct anser is 0.0000563

Step-by-step explanation:

you move the decimal point to the left 5 spaces because it is negative

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2 years ago

Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

AleksAgata [21]

we are given

$12x^3-2x^2+18x-3$

Firstly, we will split terms

$2x^2*6x-1*2x^2+3*6x-1*3$

We can group first two and last two terms

$(2x^2*6x-1*2x^2)+(3*6x-1*3)$

we can see that 2x^2 is common in first two terms

and 3 is common in last two terms

so, we can factor factor out 2x^2 from first group and 3 from second group

we get

$=2x^2(6x-1)+3(6x-1)$

we can see that each terms are multiple of 6x-1

so, we can factor out 6x-1

so, we get

$12x^3-2x^2+18x-3 =(2x^2+3)(6x-1)$ ............Answer

4 0

2 years ago

Read 2 more answers

Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $

nlexa [21]

Answer:

Step-by-step explanation:

Given that

For delivery within $1\frac{1}2$ mi, charges = $1.25

For delivery within $1\frac{1}2$ mi - $1\frac{3}4$ mi, charges = $1.70

For delivery within $1\frac{3}4$ mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2 $\frac{1}4$ mi, charges = $2.60

For delivery within 2 $\frac{1}4$ mi - 2 $\frac{1}2$ mi, charges = $3.05

For delivery within 2 $\frac{1}2$ mi - 2 $\frac{3}4$ mi, charges = $3.50

For delivery within 2 $\frac{3}4$ mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3 $\frac{1}4$ mi, charges = $4.40

So, every 0.25 mi or $\frac{1}4$ mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of $3\frac{1}8$ miles lies within the range 3 mi - 3 $\frac{1}4$ mi.

So actual charges after increase of 10%

$\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}$

6 0

2 years ago

Randal builds and sells cabinets. When deciding what price to charge for a project, he considers the cost of materials and the t

marta [7]

Answer:

3781

Step-by-step explanation:

80 hours × $18=$1440 for labor. 1440+15%(1440×.15)=$216.00 + material cost=$2125

(2125.00+1440.00+216=3781)

6 0

2 years ago

Read 2 more answers