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Andrei [34K]
2 years ago
9

Is 9.373 a repeating decimal? Is it rational? Explain your reasoning.

Mathematics
2 answers:
Galina-37 [17]2 years ago
6 0

its is not a repeating decimal and it is a rational number because a rational number is a number that does not have repeating decimal but a irrational number does have repeating decimal

-BARSIC- [3]2 years ago
4 0

Answer:

The given number is rational number.

Step-by-step explanation:

We are asked to find whether 9.373 is a repeating decimal.

Since we cannot see a bar on the digits after decimal, so our given number is not a repeating decimal.

We know that a number is rational number, when it can be represented as a fraction.

We can represent our given number as a fraction by multiplying and dividing by 1000 as:

9.373\times \frac{1000}{1000}=\frac{9373}{1000}

Therefore, our given number is a rational number.

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Minato drove 390 miles. Part of the drive was along local roads, where his average speed was 20 mph, and the rest was along a hi
pashok25 [27]

Answer:

45 miles.

Step-by-step explanation:

Given that the:

Total distance covered = 390 miles

Total time = 8 hours

Let the distance covered along the local way = L

And the distance covered along the highway = H

Along with local way,

Speed = distance/ time

20 = L / T

T = L /20 .... (1)

Along the highway,

Distance covered H = 390 - L

Let the time = t

Speed = distance/time

60 = (390 - L)/t

t = ( 390 - L)/60

But total time = T + t

That is

8 = L/20 + (390 - L)/60

The LCM at right hand side will be 60

8 = ( 3L + 390 - L )/60

Cross multiply

480 = 2L + 390

Collect the like terms

2L = 480 - 390

2L = 90

L = 90/2

L = 45 miles.

Therefore, the distance Minato drive along local roads is 45 miles

4 0
2 years ago
You roll a colored cube with one white side, two red sides, and three blue sides. What is the expected number of red sides you w
miskamm [114]

Hello!

This is an example of theoretical probability. If you rolled the die 1,000 times, you would probably roll red about 333 times. On average, this is 1/3, and with a die it is 2/6. As you can see, it will be rolled 2/6 of the time on average, so our answer is A) 2.

I hope this helps!

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The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
1 year ago
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