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Nookie1986 [14]
2 years ago
7

Alexis, Becca, and Cindy do volunteer work at Adopt-a-Pet Animal Shelter. They worked a total of 285 hours at the shelter last s

ummer. Alexis worked 15 hours less than Becca. Cindy worked 4 more than twice as many hours as Becca.
Write and solve an equation that expresses the relationship between the number of hours each student worked last summer and the total number of hours worked. Define the variable used in your equation.


How many hours did each student work?

I really need the answer to this by Monday so please help if you have the time.
Mathematics
1 answer:
swat322 years ago
3 0

Alexis worked for 59 hours, Becca worked for 74 hours and Cindy worked for 152 hours.

Step-by-step explanation:

Given,

Total hours worked by three of them = 285 hours

Let,

x represent the hours of Alexis.

y represent the hours of Becca.

z represent the hours of Cindy.

According to given statement;

x+y+z=285    Eqn 1

Alexis worked 15 hours less than Becca.

x = y-15         Eqn 2

z = 2y+4        Eqn 3

Putting value of x and z from Eqn 2 and 3 in Eqn 1

(y-15)+y+(2y+4)=285\\y-15+y+2y+4=285\\4y-11=285\\4y=285+11\\4y=296

Dividing both sides by 4

\frac{4y}{4}=\frac{296}{4}\\y=74

Putting y=74 in Eqn 2

x=74-15\\x=59

Putting y=74 in Eqn 3

z=2(74)+4\\z=148+4\\z=152

Alexis worked for 59 hours, Becca worked for 74 hours and Cindy worked for 152 hours.

Keywords: linear equation, division

Learn more about division at:

  • brainly.com/question/9510228
  • brainly.com/question/9443926

#LearnwithBrainly

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Forest park campgrounds charges $100 membership fee plus $35 per night. Woodland campgrounds Charges a $20 membership fee plus $
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Answer:

If camping for 4 nights, you should either of them since they cost the same. However, if camping for more than 4 nights, you should choose Forest park since it would be cheaper than Woodland.

Step-by-step explanation:

<em>Step 1:  compare total price for 4 nights in each campground;</em>

Forest park= 100+(4*35)= $240

Woodland= 20+(4*55)= $240

Therefore, if camping for 4 nights, you should choose either of the two because they cost the same.

<em>Step 2: compare total price for camping more than 4 nights in each campground;</em>

Assume you plan to stay for 6 nights

Forest park= 100+(6*35)= $310

Woodland= 20+(6*55)= $350

4 0
1 year ago
In a multiple choice exam, there are 5 questions and 4 choices for each question (a, b, c, d). Nancy has not studied for the exa
KonstantinChe [14]

Answer:

Part 1

a) 0.0791

b) 0.000977

c) 0.7627

Part 2

a) 0.049

b) 0.067

c) 0.864 or 0.136 (depending on what the question truly says)

d) 0.806

Step-by-step explanation:

Part 1

Since there are 4 choices per question, and only one correct answer per question.

The probability of getting a question right = (1/4) = 0.25

Probability of getting a question wrong = 1 - 0.25 = 0.75

a) Probability that the first question she gets right is the 5th question means she gets the first 4 questions wrong, and gets the last question.

0.75 × 0.75 × 0.75 × 0.75 × 0.25 = 0.0791

b) Probability that she gets all of the questions right

0.25 × 0.25 × 0.25 × 0.25 × 0.25 = 0.000977

c) Probability that she gets at least one question right = 1 - (probability that she doesn't get any question right) = 1 - (0.75⁵) = 1 - 0.2373 = 0.7627

Part 2

We use standard normal distribution for this

a) Area under (Z< -1.65) = P(z < -1.65) = 1 - P(z ≥ -1.65) = 1 - P(z ≤ 1.65) = 1 - 0.951 = 0.049

b) Area under (Z > 1.5) = P(z > 1.5) = 1 - P(z ≤ 1.5) = 1 - 0.933 = 0.067

c) P(z > -1.1) or P(z < -1.1)

P(z > - 1.1) = 1 - P(z ≤ -1.1) = 1 - 0.136 = 0.864

P(z < - 1.1) = 1 - P(z ≥ - 1.1) = 1 - P(z ≤ 1.1) = 1 - 0.864 = 0.136

d) |Z|>1.3 = P(-1.3 < z < 1.3) = P(z < 1.3) - P(z < -1.3)

P(z < 1.3) = 1 - P(z ≥ 1.3) = 1 - P(z ≤ -1.3) = 1 - 0.097 = 0.903

P(z < -1.3) = 1 - P(z ≥ -1.3) = 1 - P(z ≤ 1.3) = 1 - 0.903 = 0.097

P(z < 1.3) - P(z < -1.3) = 0.903 - 0.097 = 0.806

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A class in advanced physics is composed of 10 juniors, 30 seniors, and 10 graduate students. the final grades show that 3 of the
const2013 [10]

Solution: We are given:

Total students = 10 + 30 + 10 =50

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P(B) = \frac{18}{50}

Now the probability a student chosen at random from this class and is found to have earned an A, the probability that he or she is a senior is:

P(A|B) = \frac{P(A \cap B}{P(B)}

                 =\frac{\frac{10}{50} }{\frac{18}{50} }

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