Meeko Insurance offers an annuity with a minimum interest rate of 3% for the

a lunch stand makes a $.75 profit on each chef's salad and $1.20 profit on each caesar salad. On a typical weekday, it sells bet

tangare [24]

Answer:

50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.

Step-by-step explanation:

Suppose, the number of Chef's salad is $x$ and the number of Caesar salad is $y$

On a typical weekday, it sells between 40 and 60 Chefs salads and between 35 and 50 Caesar salads.

So, the two constraints are: $40\leq x\leq 60$ and $35\leq y\leq 50$

The total number sold has never exceed 100 salads. So, another constraint will be: $x+y\leq 100$

According to the graph of the constraints, the vertices of the common shaded region are: $(40,35), (60,35), (60,40), (50,50)$ and $(40,50)$ (Refer to the attached image for the graph)

The lunch stand makes a $.75 profit on each Chef's salad and $1.20 profit on each Caesar salad. So, the profit function will be: $P=0.75x+1.20y$

For (40, 35) , $P=0.75(40)+1.20(35)=72$

For (60, 35) , $P=0.75(60)+1.20(35)=87$

For (60, 40) , $P=0.75(60)+1.20(40)=93$

For (50, 50) , $P=0.75(50)+1.20(50)=97.5$ (Maximum)

For (40, 50) , $P=0.75(40)+1.20(50)=90$

Profit will be maximum when $x=50$ and $y=50$

Thus, 50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.

6 0

2 years ago

The paired data below consist of the temperatures on randomly chosen days and the amount a certain kind of plant grew (in millim

rjkz [21]

Answer:

Step-by-step explanation:

Given is a paired data which consist of temperatures (X in mm) and growth

We have to find the linear correlation i.e. the measure of association between these two variables.

x y xy x^2 y^2

62 36 2232 3844 1296

76 39 2964 5776 1521

50 50 2500 2500 2500

51 13 663 2601 169

71 33 2343 5041 1089

46 33 1518 2116 1089

51 17 867 2601 289

44 6 264 1936 36

79 16 1264 6241 256

Mean 58.88888889 27 1623.888889 3628.444444 916.1111111

cov 33.88888889

std dev x 13.43916333 14.50861813

sx *sy

r 0.195529176

Hence we find that correlation coefficient 0.1955.

7 0

2 years ago

Lois has a balance of $970 on a credit card with an APR of 24.2%, compounded monthly. About how much will she save in interest o

kirill115 [55]

$152.51
y o u r a n s w e r i s a b o v e

5 0

2 years ago

Read 2 more answers

25x⁴+4x⁴y²+4y⁴ answer this

vova2212 [387]

Answer:

(5x²+2y² + 2xy)(5x²+2y²-2xy)

Step-by-step explanation:

25x⁴+4x²y²+4y⁴= (5x²)²+2*5x²*2y²+(2y²)² - 16x²y²= (5x²+2y²)² - (4xy)²= (5x²+2y² + 2xy)(5x²+2y² - 2xy)

6 0

2 years ago

Let Xn be the random variable that equals the number of tails minus the number of heads when n fair coins are flipped. What is t

Firlakuza [10]

Answer:

the expected value of Xn , E(Xn) = 0 and the variance σ²(Xn) = n*(1-2n)

Step-by-step explanation:

If X1= number of tails when n fair coins are flipped , then X1 follows a binomial distribution with E(X1) = n*p , p=0,5 and the number of heads obtained is X2=n-X1

therefore

Xn =X1-X2 = X1- (n-X1) = 2X1-n

thus

E(Xn) =∑ (2*X1-n) p(X1) = 2*∑[X1 p(X1)] -n∑p(X1) = 2*E(X1)-n = 2*n*p--n= 2*n*1/2 -n = n-n =0

the variance will be

σ²(Xn) = ∑ [Xn - E(Xn)]² p(Xn) = ∑ [(2X1-n) - 0 ]² p(X1) = ∑ (4*X1²-4*X1*n+n²) p(X1) = = 4*∑ X1²p(X1) - 4n ∑X1 p(X1) - n²∑p(X1) = 2*E(X1²) -4n*E(X1)- n²

since

σ²(X1) = n*p*(1-p) = n*0,5*0,5=n/4

and

σ²(X1) = E(X1²) - [E(X1)]²

n/4 = E(X1²) - (n/2)²

E(X1²) = n(n+1)/4

therefore

σ²(Xn) = 4*E(X1²) -4n*E(X1)- n² = 4*n(n+1)/4 - 4*n*n/2 - n² = n(n+1) - 2n² - n²

= n - 2n² = n(1-2n)

σ²(Xn) = n(1-2n)

4 0

1 year ago