Ask question

Ask question

All categories

2 years ago

13

The paired data below consist of the temperatures on randomly chosen days and the amount a certain kind of plant grew (in millim

eters): Temp 62 76 50 51 71 46 51 44 79 Growth 36 39 50 13 33 33 17 6 16 Find the value of the linear correlation coefficient r.

1 answer:

rjkz [21]2 years ago

7 0

Answer:

Step-by-step explanation:

Given is a paired data which consist of temperatures (X in mm) and growth

We have to find the linear correlation i.e. the measure of association between these two variables.

x y xy x^2 y^2

62 36 2232 3844 1296

76 39 2964 5776 1521

50 50 2500 2500 2500

51 13 663 2601 169

71 33 2343 5041 1089

46 33 1518 2116 1089

51 17 867 2601 289

44 6 264 1936 36

79 16 1264 6241 256

Mean 58.88888889 27 1623.888889 3628.444444 916.1111111

cov 33.88888889

std dev x 13.43916333 14.50861813

sx *sy

r 0.195529176

Hence we find that correlation coefficient 0.1955.

You might be interested in

A rectangle has a perimeter of 18 inches. a new rectangle is formed by doubling the with W in tripling the length L as shown the

vladimir1956 [14]

a) The dimensions of original rectangle are length= 5 and width= 4.

b) The dimensions of new rectangle are length= 15 and width=8.

<u>Step-by-step explanation</u>:

length of a rectangle = l
width of a rectangle = w
Perimeter of a rectangle = 2(l+w)

<u>Original rectangle</u> :

18 = 2(l+w)

18 = 2l + 2w ---------(1)

<u>New rectangle</u> :

46 = 2(3l+2w)

46 = 6l + 4w ---------(2)

<u>Solving the equations</u> :

Multiply (1) by 2 and subtract (2) from (1)

4l + 4w = 36

-(<u>6l + 4w = 46</u>)

<u>-2l = -10</u>

l = 10/2

length = 5 inches.

Substitute l=5 in (1)

18 = 2(5)+2w

18 = 10+2w

2w = 8

w = 8/2

width = 4 inches.

length of new rectangle = 3(l) = 3 $\times$ 5 = 15 inches.

width of new rectangle = 2(w) = 2 $\times$ 4 = 8 inches.

8 0

1 year ago

Bill drives and sees a red light. He slows down to a stop. A graph of his velocity over time is shown below. What is his average

Feliz [49]

Answer:

0

Step-by-step explanation:Velocity at t= 0s is 20m/s and the velocity at t= 10s is 20m/s.

a= 20-20/ 10s

a=0m/s

4 0

1 year ago

What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

in this problem we have

the point $(5,12)$ is on the line of direct variation

so

Find the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

the equation is

$y=\frac{12}{5}x$

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

<u>case A)</u> point $(0,0)$

$x=0\ y=0$

Substitute the value of x and y in the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is true

therefore

the point $(0,0)$ is on the line of direct variation

<u>case B)</u> point $(2.5,6)$

$x=2.5\ y=6$

Substitute the value of x and y in the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is true

therefore

the point $(2.5,6)$ is on the line of direct variation

<u>case C)</u> point $(3,10)$

$x=3\ y=10$

Substitute the value of x and y in the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not true

therefore

the point $(3,10)$ is not on the line of direct variation

<u>case D)</u> point $(7.5,18)$

$x=7.5\ y=18$

Substitute the value of x and y in the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is true

therefore

the point $(7.5,18)$ is on the line of direct variation

<u>case E)</u> point $(12.5,24)$

$x=12.5\ y=24$

Substitute the value of x and y in the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not true

therefore

the point $(12.5,24)$ is not on the line of direct variation

<u>case F)</u> point $(15,36)$

$x=15\ y=36$

Substitute the value of x and y in the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is true

therefore

the point $(15,36)$ is on the line of direct variation

therefore

<u>the answer is</u>

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

1 year ago

Read 2 more answers

A full bag of dog food weighs 5 1 2 pounds. How much dog food do you have if there are 3 3 4 bags in the cupboard

Ulleksa [173]

You would have 171,008 lbs. of dog food. Because 512 pounds times 334 bags equals 171,008lbs.

6 0

1 year ago

Read 2 more answers

What is the value of x? Enter your answer, as a decimal, in the box. x= A right triangle with vertices labeled as A, B, and C. S

____ [38]

x=3.95

Explanation

From the given information we find that the triangle is right angled at C. CB is the base,AC is the height and AB is the hypotenuse.

Given that D is the hypotenuse of the hypotenuse AB.

BC=6

BD=4.2

AD=x

the height and the base of the triangle is given.

Using pythagoras theorem, we can find the hypotenuse AB.

$AB=\sqrt{AC^2+CB^2} \\=\sqrt{5^2+6^2} \\=\sqrt{25+36} \\=\sqrt{61} \\$

D is the midpoint of AB

therefore AD=AB/2= $\sqrt{61}/2$

=3.905

x=3.905 cm

6 0

1 year ago