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2 years ago

NEED HELP FAST WILL GIVE BRAINIEST

Mathematics

2 answers:

vladimir1956 [14]2 years ago

5 0

Answer:

x^2 + 8x - 65 = 0.

Step-by-step explanation:

In order to solve the side of the enlarged area of 81 square inches, we use the equation in solving the area of a square. Area = side^2.

the increase in side will be x, so (4+x)^2 = 81, x^2 + 4x + 4x + 16 = 81

x^2 + 8x + 16 - 81 = 0

x^2 + 8x - 65 = 0.

Hoped this helped mark Brainliest!

almond37 [142]2 years ago

4 0

to solve the side of the area of 81 square inches

use the equation in solving the area of a square. Area = side^2.

the increase in side will be x, so (4+x)^2 = 81, x^2 + 4x + 4x + 16 = 81

x^2 + 8x + 16 - 81 = 0

x^2 + 8x - 65 = 0.

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In ΔMNO, the measure of ∠O=90°, ON = 65, MO = 72, and NM = 97. What is the value of the tangent of ∠M to the nearest hundredth?

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Answer:

Therefore the value of tangent of ∠ $M$ is $42$ °.

Step-by-step explanation:

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In Δ $MNO$ , ∠ $O=90$ °, $ON=65,$ $MO=72,$ and $NM=97.$

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Diagram of the given triangle is shown below:

Now,

Δ $MNO$ is a right angle triangle, so we can use all the trigonometric ratio.

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$tan\alpha =\frac{sin\alpha }{cos\alpha }$ = $\frac{Perpendicular}{Base}$

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